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Leno4ka [110]
3 years ago
5

Water will move from a ____________ salt solution to a ____________ salt solution when they are across a differentially permeabl

e membrane.
Chemistry
1 answer:
const2013 [10]3 years ago
6 0
The answers are low concentrated (dilute) and high concentrated respectively. 

As the low concentrated salt solution has a higher water potential than that of the high concentrated salt solution, water molecules will flow from the region of higher water potential to the region of lower water potential, thus from the dilute salt solution to the high concentrated salt solution. This is due to the movement called osmosis. Note that osmosis also requires water to flow through a differentially permeable membrane, which means the membrane can allow certain substances (not all) to go in or out. If the differentially permeable membrane is not present, the movement of water molecules may be regarded as diffusion. 

Therefore, the answers for the blanks are low concentrated and high concentrated.




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helium gas in a 2.00 L cylinder is under 1.12 atm pressure. At 36.5°C that same gas sample has a pressure of 2.56 atm. What was
Irina18 [472]

Answer:

T₁ = 135.41 K

Explanation:

Given data:

Initial pressure = 1.12 atm

Finial temperature = 36.5 °C (36.5 +273 = 309.5 K)

Initial temperature = ?

Final pressure = 2.56 atm

Formula:  

P₁/T₁ = P₂/T₂  

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Solution:

P₁/T₁ = P₂/T₂  

T₁  = P₁T₂  /P₂

T₁ = 1.12 atm × 309.5 K / 2.56 atm

T₁ = 346.64 atm . K / 2.56 atm

T₁ = 135.41 K

5 0
3 years ago
What is the mass of 4.32 mol GaI3?<br><br> A. 455 g<br> B. 1,230 g<br> C. 1,720 g<br> D. 1,950 g
Sliva [168]
The answer is D.1.950 g

The sponsoring editor for this book was Kenneth P. McCombs and the production supervisor was Sherri Souffrance. It was set in Times Roman by International Typesetting and Composition. The art director for the cover was Anthony Landi. Printed and bound by RR Donnelley.

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5 0
3 years ago
Read 2 more answers
What minimum volume of 0.200 m potassium iodide solution is required to completely precipitate all of the lead in 195.0 ml of a
lbvjy [14]
First, we write the reaction equation:

2KI + PbNO₃  → K₂NO₃ + PbI₂
The molar ratio of KI to PbNO₃ is 2 : 1
Moles of PbNO₃ present:
Moles = concentration (M) x volume (dm³)
= 0.194 x 0.195
= 0.038
Moles of KI required = 2 x 0.038 = 0.076 moles
concentration = moles / volume
volume = moles / concentration
= 0.076 / 0.2
= 0.38 L = 380 ml
7 0
3 years ago
In a particular experiment, 2.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.
Neporo4naja [7]

Answer:

4.18 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given: For Li

Given mass = 2.50 g

Molar mass of Li  = 6.94 g/mol

<u>Moles of Li  = 2.50 g / 6.94 g/mol = 0.3602 moles</u>

Given: For N_2

Given mass = 2.50 g

Molar mass of N_2 = 28.02 g/mol

<u>Moles of N_2 = 2.50 g / 28.02 g/mol = 0.08924 moles</u>

According to the given reaction:

6Li+N_2\rightarrow 2Li_3N

6 moles of Li react with 1 mole of N_2

1 mole of Li react with 1/6 mole of N_2

0.3602 mole of Li react with \frac {1}{6}\times 0.3602 mole of N_2

Moles of N_2 that will react = 0.06 moles

Available moles of N_2 = 0.08924 moles

N_2 is in large excess. (0.08924 > 0.06)

Limiting reagent is the one which is present in small amount. Thus,

Li is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

6 moles of Li gives 2 mole of Li_3N

1 mole of Li gives 2/6 mole of Li_3N

0.3602 mole of Li react with \frac {2}{6}\times 0.3602 mole of Li_3N

Moles of Li_3N = 0.12

Molar mass of Li_3N = 34.83 g/mol

Mass of Li_3N = Moles × Molar mass = 0.12 × 34.83 g = 4.18 g

<u>Theoretical yield = 4.18 g</u>

5 0
3 years ago
Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. If 70.8 g of c
Rus_ich [418]

Answer:

1.18 moles of CS₂ are produced by the reaction.

Explanation:

We present the reaction:

5C + 2SO₂  →  CS₂  +  4CO

5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.

As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles

8 0
3 years ago
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