when 1.00 l 1.00 l of a 0.500 m l i b r 0.500 m libr solution is tripled by dilution with water, what is the number of moles of

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9 months ago

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lithium in the new solution

1 answer:

Murrr4er [49] · Answer 1 · 2024-05-09T13:10:19+03:00

When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.

given that :

volume = 1.00 L

molarity = 0.500 M

The solution is tripled by dilution but there will be no effect in number of mole by the dilution.

the number of moles = molarity × volume in L

the number of moles = 1 × 0.500

the number of moles = 0.5 mol

Thus, When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.

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