Answer:
The plum pudding model would have to be true as well because it shows that electrons are scattered within an atom.
Explanation:
I took the test and got it right :)
my mom because she is my mom
Answer:
The formation of large molecules from small repeating units is known as <u>Condensation</u> reactions.
Explanation:
Those reactions in which two molecules join together with a elimination of small neutral molecule like H₂O, CH₃OH, HCl e.t.c are known as condensation reactions.
Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms among which one is the condensation reaction.
Example:
Proteins (polymer) are made up of amino acids (monomers) through condensation reaction as,
n H₂N-RH-COOH → H₂N-[-RH]n-COOH + n H₂O
In above equation "n" represent large number, H₂N-RH-COOH represent amino acid (monomer) and H₂N-[-RH]n-COOH represent protein (polymer). While, the H₂O eliminated is the small neutral molecule.
Answer:
After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.
Explanation:
Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:
ln[HI] = -kt + ln [HI]₀
<em>Where [HI] is actual concentration after time t, </em>
<em>k is rate constant </em>
<em>and [HI]₀ is initial concentration of the reactant.
</em>
Initial concentration of HI is 0.310M,
K is 0.0660s⁻¹,
And the actual concentration is 0.0558M:
ln[HI] = -kt + ln [HI]₀
ln[0.0558M] = -0.0660s⁻¹*t + ln [
0.310M]
-1.7148 = -0.0660s⁻¹*t
26.0s = t
<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>
<em />
The reaction is: HCl + Na HCO3 → NaCl + H2CO3, which is already balanced.
Then the molar ratios are 1 mol HCL : 1 mol NaHCO3
You know the mass of NaHCO3 is 0.100 g, then you can find the number of moles using the molar mass of NaHCO3
molar mass of NaHCO3 is 23 g/mol + 1 g/mol + 12g/mol + 3*16g/mol = 84 g/mol
And the number of moles is: 0,100 g / 84 g/mol = 0,0012 mol of NaHCO3.
Then, from the ratio 1:1, you know that, at the titration point, the number of moles of HCl is the same: 0,0012 mol of HCl.
Now from the fomula of molarity you have: M = #of moles / V in liters
=> V in liters = # of moles / M = 0.0012 mol / 0.100 M = 0.012 liters
Answer: 0.012 liters of HCL
