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3 years ago

What do diamonds , the lead in pencils and coal have in common?

Chemistry

1 answer:

barxatty [35]3 years ago

8 0

They are all products of carbon

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Which substance is an example of a nonpolar compound?(1 point)

Tatiana [17]

The answer is B - vegetable oil.

Explanation:

The properties of liquids depend on the attractions the molecules of the liquid have for each other and for other substances.

Liquids can dissolve certain other liquids, depending on the attractions between the molecules of both liquids.

Polar liquids, like water, dissolve other liquids which are polar or somewhat polar.

Polar liquids, like water, do not dissolve non-polar liquids like oil.

8 0

3 years ago

Please help me I will give you the brain thing and extra points. image below part 8

Marizza181 [45]

The correct answer should be D :)

8 0

2 years ago

Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of CH4 is required to completely react with 100 grams of

AfilCa [17]

Answer:

The mass methane (CH4) required is, 25 grams (option C)

Explanation:

Mass of oxygen gas = 100 g

Molar mass of oxygen gas = 32 g/mole

Molar mass of methane gas = 16 g/mole

Step 1: Balance the reaction

2O2 + CH4 → CO2 + 2H2O

Step 2: Calculate the moles of O2:

Moles O2 = mass of O2 / Molar mass of o2

Moles O2 = 100g / (32g/mole) = 3,125 moles

⇒From the balanced reaction we conclude that 2 moles of O2 react with 1 mole of CH4

⇒ So, 3.125 moles of O2 react with 3.125/2 = 1.563 moles of CH4

Step 3: Calculate the mass of CH4:

Mass of CH4 = moles of CH4 x Molar mass of CH4

Mass of CH4 = 1.563 moles / (16g/ moles) = 25.008 grams CH4

6 0

3 years ago

The most characteristic property of the noble gases is that they

Brut [27]

Answer:

odorless and colorless

Explanation:

its their properties

7 0

2 years ago

A gas has a volume of 350 mL at 318.15 K. If the volume changes to 4.00 L, what is the new temperature?

enot [183]

28°C.
Explanation:
The correct equation to use with these kinds of questions is the Combined Gas Law.
P
1
⋅
V
1
T
1
=
P
2
⋅
V
2
T
2
This equation, though, is a little unnecessary at times because of the possibility of extra constants.
In this case you have a pressure constant which enables us to shorten your longer equation down to Charles' Law because pressure remains the same and doesn't affect the calculation.
V
1
T
1
=
V
2
T
2
The next step is to isolate the variable that you want, which is, in this case,
T
2
.
T
2
=
V
1
T
1
V
2
Now it is time to replace your known variables with numbers
T
2
=
350
m
L
⋅
45
°
C
400
m
L
And calculate...
T
2
=
28.125
°
C
Significant digits...
T
2
=
28
°
C

7 0

2 years ago