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kakasveta [241]
1 year ago
8

Gold (Au) should have an electron notation that ends in 6s24f145d9. To become more stable, the electrons in reality rearrange th

emselves. How do they do it
Chemistry
1 answer:
STALIN [3.7K]1 year ago
6 0

The electrons rearrange themselves to ensure that orbitals at lower energy levels are first filled before those at higher energy levels.

<h3>Electronic configuration</h3>

One of the rules of electronic configuration states that lower energy level orbitals are first filled with electrons before higher energy level orbitals.

Thus, the electrons in Gold will rearrange themselves to obey the above rule in order to achieve more stability.

Hence, the electronic configuration becomes: 4f^{14}, 5d^{10} ,6s^1

More on electronic configuration can be found here: brainly.com/question/14283892

#SPJ2

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The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
Which of the following correctly pairs a phase of
Harrizon [31]

Answer:

njhhhhhhh

Explanation:

8 0
3 years ago
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What is the density of a solid that has a mass of 9.2 grams and a volume of 12.3 cm3 ? Would this object float or sink in water?
cluponka [151]
  • Mass=9.2g
  • Volume=12.3

\boxed{\sf Density=\dfrac{Mass}{Volume}}

\\ \sf\longmapsto Density=\dfrac{9.2}{12.3}

\\ \sf\longmapsto Density=0.74g/cm^3

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It will float in water

7 0
3 years ago
Identify whether the following example is qualitative or quantitative data.
OLga [1]
I think that it is qualitative data
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Why are hydrogen bonds so essential to the structure of dna?
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Hydrogen bonds<span> hold the paired nitrogenous bases together. Because </span>hydrogen bonds<span> are weak </span>bonds<span>, the two strands of </span>DNA<span> are easily separated a characteristic that is important to </span>DNA's<span> function.</span>Hydrogen bonds<span> form between adenine and thymine and between cytosine and guanine.</span>
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3 years ago
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