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3 years ago

Which would not be associated with stable atmospheric conditions

Chemistry

2 answers:

dlinn [17]3 years ago

7 0

The correct answer is - afternoon thunder showers.

When we say stable atmospheric conditions it means that the atmosphere should be relatively calm, without having any disturbances in it. A nice example for a stable atmospheric conditions is a clear sunny sky and a calm wind. On the other hand, we have the afternoon thunder showers. The afternoon thunder showers are the total opposite of stable atmospheric conditions. When they occur, there's lot of disturbances, air pressures are mixing, the winds are changing speeds, heavy rainfall occurs, the air pressure changes rapidly, there's electrical charges, all in all creating a real mess in the atmosphere.

Genrish500 [490]3 years ago

5 0

Answer:

afternoon thunder showers.

Explanation:

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3 years ago

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

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