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3 years ago

Which would not be associated with stable atmospheric conditions

Chemistry

2 answers:

dlinn [17]3 years ago

7 0

The correct answer is - afternoon thunder showers.

When we say stable atmospheric conditions it means that the atmosphere should be relatively calm, without having any disturbances in it. A nice example for a stable atmospheric conditions is a clear sunny sky and a calm wind. On the other hand, we have the afternoon thunder showers. The afternoon thunder showers are the total opposite of stable atmospheric conditions. When they occur, there's lot of disturbances, air pressures are mixing, the winds are changing speeds, heavy rainfall occurs, the air pressure changes rapidly, there's electrical charges, all in all creating a real mess in the atmosphere.

Genrish500 [490]3 years ago

5 0

Answer:

afternoon thunder showers.

Explanation:

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Alenkinab [10]

Answer:

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8 0

3 years ago

what is the temperature in Kelvin of 5.00 moles of nitrogen gas in a 30 L container with a pressure of 4.00 atm

Marianna [84]

The temperature of the nitrogen gas is 292.5 K.

Explanation:

Given that

Moles of Nitrogen, n = 5 mol

Volume, V = 30 L

Pressure, P = 4 atm

Gas Constant, R = 0.08205 L atm mol⁻¹ K⁻¹

Temperature = ? K

We have to use the ideal gas equation,

PV = nRT

by rearranging the equation, so that the equation becomes,

T = $$\frac{PV}{nR}\\$

Plugin the above values, we will get,

T = $$\frac{4 \times 30}{5 \times 0.08205}$

= 292.5 K

So the temperature of the nitrogen gas is 292.5 K.

7 0

3 years ago

When 240 mg of a certain molecular compound X are dissolved in 35.0 g of dibenzyl ether ((C6H5CH2)2O), the freezing point of the

DedPeter [7]

Answer: MM = 16.55 g/mol

Explanation: Freezing point depression is a phenomena that explains why adding a solute to a solvent decreases the solvent freezing point: when a substance begins to freeze, its molecules slows down and rearrange itself forming a solid. If a solute is added, the molecules from the solvent interfere in the formation of the solid. To guarantee the transformation, the solution has to cooled down even more.

Freezing point and molality concentration is related by

$\Delta T=T_{f}_{(solvent)}-T_{f}_{(solution)}=K_{f}.m$