CH_3 CH_2 Cl has two different types of hydrogen. On further chlorination they are being substituted by chlorine to give two isomeric dichlorides
The structures of the two chlorides are shown below.
Where Hb is replaced by Cl and Ha is replaced by Cl
The first step is to find the number of moles of OH⁻ that reacted with the HCl. To do this multiply 2.00L by 1.50M to get 3 moles of Ca(OH)₂. Then you multiply 3 by 2 (there are 2 moles of OH⁻ per every 1 mole of Ca(OH)₂) to get 6 moles of OH⁻. That means that you needed 6 moles of HCl since 1 mole of HCl contains 1 mole of H⁺ and equal amounts H⁺ and OH⁻ reacted with each other. To find the molarity of the HCl solution you need to divide 6mol by 1L to get 6M. Tat means that the concentration of the acid was 6M.
I hope this helps. Let me know if anything was unclear.
Answer:
I and IV are the correct answers
Explanation:
The balanced equation :
4Fe + 3O₂⇒ 2Fe₂O₃
<h3>Further explanation</h3>
Given
Rust reaction
Required
Balanced equation
Solution
Reaction
Fe + O₂⇒ 2Fe₂O₃
For a simple equation where one of the reaction coefficients is known, we can immediately add the corresponding coefficient using the principle that the number of atoms of <em>the components in the reactants and products is the same.
</em>
In the above reaction :
Fe, left=1, right = 4, so coefficient in the left=4
O, left=2, right = 6, so coefficient in the left=3
Q. What type of radioactive decay involves two protons and two neutrons?
A. Alpha emission
