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STatiana [176]
3 years ago
7

Five dices are tossed together, what is the total number of outcome expected from this experiment?

Mathematics
1 answer:
Serga [27]3 years ago
3 0
The total number of outcomes would be 6 ;) Hope this helps!
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A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two
Vikentia [17]

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

Y \sim P( \beta = 2)

the probability mass function can be represented as follows:

\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}

where;

y =  0,1,2,3 ...

Hence,  the probability of no defects in 10 feet of steel

y = 0

\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}

\mathtt{P(y =0) = \dfrac{0.1353  \times 1}{1}}

P(y =0) = 0.1353

4 0
3 years ago
1.
Yuliya22 [10]

Answer:

C (-2, 0)

Step-by-step explanation:

y = x+2

intersect the x-axis when y = 0, then

0 = x+2

x = -2

7 0
3 years ago
Consider the trapezoid with given dimensions. Suppose it is dilated by a scale factor of
koban [17]

Answer: 1 & 4

Step-by-step explanation:

Just did it

6 0
3 years ago
015: Rectangle homework
yaroslaw [1]

Answer:

Length: 6 ft

Width: 4 feet

Step-by-step explanation:

Length: L

Width: 2L - 8

2L + 2(2L - 8) = 20

2L + 4L - 16 = 20

6L = 36

L = 36/6

L = 6

W= 2(6)-8 = 4

7 0
3 years ago
A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred
Sergio039 [100]

Answer:  0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = \dfrac{0.63}{3}

=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

2\times0.21=0.42\ mg

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

6 0
3 years ago
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