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Dvinal [7]
4 years ago
7

Ice (H2O) melting at 273 K and 1 atm has = 6.01 kJ/mol and = 6.01 kJ/mol while water vaporizing under the same conditions has =

37.6 kJ/mol and = 40.7 kJ/mol. Why is there such a large difference between and , but not for and ?
Chemistry
1 answer:
Soloha48 [4]4 years ago
5 0

Answer:

Degree of intermolecular hydrogen bonding

Explanation:

The energy required to melt a solid substance and the temperature at which the solid melts depends on the structure of the solid crystal as also on the magnitude of the intermolecular forces present in the solid.

Ice is less dense than liquid water, there are spaces in the crystal structure of ice. Secondly, the magnitude of hydrogen bonding in ice is lower due to lower intermolecular interaction between the water molecules. Given the lower intermolecular interaction in ice, the heat of fusion is much lower since the intermolecular interactions are easier to break.

In liquid water, hydrogen bonding is much stronger and there is greater intermolecular interaction between the water molecules. It takes more energy to break down these intermolecular interactions, hence the high enthalpy of vaporization of liquid water.

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Which of the following statements are true? (There are 2)
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Answer:

A and B

Explanation:

the other two make no sense at all

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3 years ago
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Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



5 0
3 years ago
Which property of a body cannot be changed if a force is applied to it?
prohojiy [21]
The answer is it’s mass
8 0
3 years ago
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Which mixture can be separated based on differences in the particle size of the components?
Rina8888 [55]

Answer: Mixtures you can separate are like cereal and milk. Hope that helps

Explanation:  Filteration is required to separate a mixture.

So heterogeneous mixures (that contain substances with different particle sizes)  can be separated with a filter.  

Homogeneous mixtures are uniform in composition so they will not be able to be separated.

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3 years ago
What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

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Br2 + S2032- + 5H20 -- >  BR2- + 2S02- + H+

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8 0
3 years ago
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