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Answer:
37.1g are produced
Explanation:
The combustion of C₈H₁₈ is:
C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O
<em>Where 1 mole of C₈H₁₈ produce 8 moles of CO₂</em>
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To find the mass of CO₂ that is produced we need to convert the mass of C₈H₁₈ with molar mass. Then, with the chemical equation, we can find the moles of CO₂ and its mass, as follows:
<em>Moles C₈H₁₈ -Molar mass: 114.2g/mol-</em>
12g C₈H₁₈ * (1mol / 114.2g) = 0.105 moles of C₈H₁₈
<em>Moles CO₂:</em>
As 1 mole of C₈H₁₈ produce 8 moles of CO₂, 0.105 moles of C₈H₁₈ produce:
0.105 moles of C₈H₁₈ * (8moles CO₂ / 1mole C₈H₁₈) = 0.84 moles of CO₂
<em>Mass CO₂ -Molar mass: 44.01g/mol-:</em>
0.84 moles of CO₂ * (44.01g / mol) = 37.0g of CO₂ ≈
<h3>37.1g are produced</h3>
It is True. Hope this helped.
P (phosphorous ) = 30.97 g/mol<span> * 2 = 61.94 g/mol.</span>
<span>O ( oxygen ) = </span>16.00 g/mol<span> * 8 = 128.00 g/mol.</span>
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<span>Calcium Phosphate Ca3(PO4)2 = </span>310.18 g/mol<span>. </span>
Sorry but I can’t help you. The image is blurry and therefore the supposition is incorrect . But 12/4 equals 3
