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goblinko [34]
3 years ago
12

Which property of a body cannot be changed if a force is applied to it?

Chemistry
2 answers:
prohojiy [21]3 years ago
8 0
The answer is it’s mass
Luden [163]3 years ago
7 0

Answer:

it's mass

Hope this helps sorry if it's wrong

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10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what
igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0
2 years ago
I need to find the orbit notation<br> 1. Ne - 1s 2s 2p 3s 3p 4s 3d 4p 5s​
weeeeeb [17]

Answer:

1s*2 2s*2 2p*6

Explanation:

atomic number of neon is 10 so the s-shell contains 2 electron and p-shell contains 6

3 0
3 years ago
The steam engine in a train heats water until it becomes steam. The steam pushes pistons to move the train. The train is changin
Strike441 [17]
The answer to your question is option A.
8 0
3 years ago
What is the temperature of a gas that is expanded from 3.75 L at 37 degrees Celsius to 5.6 L?
deff fn [24]

Answer:

190 °C  

Step-by-step explanation:

The pressure is constant, so this looks like a case where we can use <em>Charles’ Law</em>:  

V₁/T₁ = V₂/T₂      Invert both sides of the equation.  

T₁/V₁ = T₂/V₂      Multiply each side by V₂

T₂ = T₁ × V₂/V₁

=====

V₁ = 3.75 L; T₁ = (37 + 273.15) K = 310.15 K  

V₂ = 5.6 L;   T₂ = ?  

=====

T₂ = 310.15 × 5.6/3.75

T₂ = 310.15 × 1.49

T₂ = 463 K

t₂ = 463 – 273.15

t₂ = 190 °C

3 0
3 years ago
How many liters of 1.75 M solution could be made using 35 grams of NaCl?
dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
1.75 =  \frac{35}{58.44*V}
1.75*58.44V = 35
102.27V = 35
V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
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