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stepladder [879]
3 years ago
5

Chlorine has two isotopes, 35Cl and 37Cl that have the respective percent abundance's of 75.77% and 24.23% and masses of 34.9688

amu and 36.9659 amu. Calculate the atomic weight of chlorine.
Chemistry
1 answer:
AnnyKZ [126]3 years ago
3 0

Answer:

The answer to your question is  35.4527 g

Explanation:

Data

Cl-35    abundance = 75.77 %    mass Cl-35 = 34.9688

Cl-37     abundance = 24.23 %   mass Cl-37 = 36.9659

Process

1.- Convert the percents to decimals

   75.77% = 75.77/100 = 0.7577

   24.23% = 24.23/100 = 0.2423

2.- Find the atomic weight

    Average atomic weight = Abundance 1 x Mass Cl-35 +

                                               Abundance 2 x Mass Cl-37

Substitution

     Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)

Simplification

     Average atomic weight = 26.4959 + 8.9568

Result

      Average atomic weight = 35.4527 g

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
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<u>Step 1: Define</u>

[Given] 1.7 × 10²⁵ molecules CaF

[Solve] moles CaF

<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                          \displaystyle 1.7 \cdot 10^{25} \ molecules \ CaF(\frac{1 \ mol \ CaF}{6.022 \cdot 10^{23} \ molecules \ CaF})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 28.2298 \ moles \ CaF

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

28.2298 mol CaF ≈ 28 mol CaF

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