Answer:
See explanation
Explanation:
A. This is a neutralization reaction.
Molecular equation;
HBr(aq) + CsOH(aq) ---------> CsBr(aq) + H20(l)
Complete ionic equation;
H^+(aq) + Br^-(aq) + Cs^(aq) + OH^-(aq) --------> Cs^+(aq) + Br^- + H20(l)
Net ionic equation;
H^+(aq) + OH^-(aq) --------> H20(l)
B. This is a gas forming reaction;
H2SO4(aq) + Na2CO3(aq) ------->Na2SO4(aq) + H2O(l) + CO2(g)
Complete ionic equation;
2H^+(aq) + SO4^-(aq) + 2Na^+(aq) + CO3^2-(aq) ------->2Na^+(aq) + SO4^-(aq) + H2O(l) + CO2(g)
Net ionic equation;
2H^+(aq) + CO3^2-(aq) -------> + H2O(l) + CO2(g)
C. This a precipitation reaction
Molecular equation;
CdCl2(aq) + Na2S(aq) ------->CdS(s) + 2NaCl(aq)
Complete ionic equation;
Cd^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + S^2-(aq) ---------> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)
Net ionic equation;
Cd^2+(aq) + S^2-(aq) ---------> CdS(s)
Answer: 3
Explanation: You may not always get feedback that would be helpful and requesting the answer would be cheating
Dependent variable. the independent is non dependent of the variable.
Explanation:
The given precipitation reaction will be as follows.

Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity = 
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity = 
0.269 M = 
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles = 
0.307 mol = 
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.
A + B → AB: ✔ synthesis
AB → A + B: ✔ decomposition
Hydrocarbon + O2 → CO2 + H2O: <span>✔ combustion</span>
AB + CD → AD + CB: <span>✔ replacement</span>