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Inga [223]
2 years ago
9

Automobile engines contain cooling systems that transfer thermal energy from the engine to the environment. Without a cooling sy

stem, how would
the temperature of the engine be affected as its operating speed increases?

A The temperature would increase
B The temperature would decrease
C The temperature would stay the same
Chemistry
1 answer:
vovangra [49]2 years ago
6 0

When the engine's <em>operating speed increases</em> the temperature of the engine will also increase.

Given:

Automobile engines without a cooling system.

To find:

The affect on the temperature of the engine as its operating speed increases.

Solution:

The speed of the operating engine increases.

  • As we know that kinetic energy of the object and motion of the object is directly proportional<em> </em>to each other.

<em>Velocity </em><em>of object </em><em>∝ Kinetic energy </em><em>of object...[i]</em>

  • When the<em> kinetic energy</em> of the object increases the kinetic energy of the particles of the object also increases.
  • And <em>kinetic energy</em> of the particles is directly linked to the <em>temperature </em>of the object.

<em>Kinetic energy</em><em>  ∝ </em><em>Temperature </em><em>of object</em>...[ii]

From [i] and [ii] :

<em>Velocity </em><em>of object ∝  </em><em>Temperature </em><em>of an object</em>

  • When the engine's operating speed increases it will increase the kinetic energy of its particles and with that increase, the increase in the temperature of the engine will be <em>observed</em>.

So, from this, we can conclude when the engine's operating speed increases the temperature of the engine will also increase.

Learn more about kinetic energy and temperature here:

brainly.com/question/2731193?referrer=searchResults

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At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre
Novosadov [1.4K]

Answer:

V₂ =  45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa  

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2 years ago
The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos
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Answer:

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

Explanation:

Mass of Earth =5.9\times 10^{21} tons

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth =5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g

Percentage of earth crust = 0.50%

Mass of earth crust = M

0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100

M=2.6762\times 10^{25} g

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

Si\%=\frac{m}{M}\times 100

27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100

m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

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