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Inga [223]
2 years ago
9

Automobile engines contain cooling systems that transfer thermal energy from the engine to the environment. Without a cooling sy

stem, how would
the temperature of the engine be affected as its operating speed increases?

A The temperature would increase
B The temperature would decrease
C The temperature would stay the same
Chemistry
1 answer:
vovangra [49]2 years ago
6 0

When the engine's <em>operating speed increases</em> the temperature of the engine will also increase.

Given:

Automobile engines without a cooling system.

To find:

The affect on the temperature of the engine as its operating speed increases.

Solution:

The speed of the operating engine increases.

  • As we know that kinetic energy of the object and motion of the object is directly proportional<em> </em>to each other.

<em>Velocity </em><em>of object </em><em>∝ Kinetic energy </em><em>of object...[i]</em>

  • When the<em> kinetic energy</em> of the object increases the kinetic energy of the particles of the object also increases.
  • And <em>kinetic energy</em> of the particles is directly linked to the <em>temperature </em>of the object.

<em>Kinetic energy</em><em>  ∝ </em><em>Temperature </em><em>of object</em>...[ii]

From [i] and [ii] :

<em>Velocity </em><em>of object ∝  </em><em>Temperature </em><em>of an object</em>

  • When the engine's operating speed increases it will increase the kinetic energy of its particles and with that increase, the increase in the temperature of the engine will be <em>observed</em>.

So, from this, we can conclude when the engine's operating speed increases the temperature of the engine will also increase.

Learn more about kinetic energy and temperature here:

brainly.com/question/2731193?referrer=searchResults

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Na + CI2 =2NaC is It balanced
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Answer:

no, the correct answer is NaCI

Explanation:

you're welcome

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When one material is rubbed against another, electrons jump readily from one to the other. why don’t protons do that?
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Protons are held inside nucleous with neutrons with large amount of force. So mere rubbing doesn't help in breaking the nucleous of an atom. But electrons are far from the nucleous and the force of attraction is smaller. So electrons can jump readily while protons can't
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A substance is made up of slow-moving particles that have very little space between them. Based on this information,
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It is not a gas because its particles do not have large space between them.

5 0
2 years ago
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The volume of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is equal to
Lubov Fominskaja [6]

Answer:

.

.

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8 0
2 years ago
If the distance between two objects is decreased to - of the original
Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

F = G\frac{m_1m_2}{R^2}The problem states  that  the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R

And the force at this distance would be written in terms of the same equation:

F_2 = G\frac{m_1m_2}{R_2^2}

Find the ratio between the final and the initial force:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}

Substitute the value for the final distance in terms of the initial distance:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}

Simplify:

\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}

This means the new force will be \frac{1}{100} of the original force.

8 0
3 years ago
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