Question

4. A sample of nitrogen at 20 degrees Celsius was compressed to 300ml to

Answer 1

Answer:

We are given:

V(i) = 0.3 L                          V(f) = 0.36 L

P(i) = x pa                            P(f) = 400 pa

T(i) = T(f) = 293 k

Using the gas formula:

PV = nRT

Since n , R and T are constant,

PV = k  (where k is a constant)

Hence we can say that:

P(i) * V(i) = P(f) * V(f)

x * 0.3 = 0.36 * 400

x = 14.4/0.3

x = 480 pascals

Hence the initial pressure is 480 pascals

Converting to Kpa, we have to divide by 1000

Initial pressure (Kpa) = 0.48