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77julia77 [94]
2 years ago
12

Hydrogen can be prepared on a small scale by the hydrolysis of metal hydrides:

Chemistry
1 answer:
lara [203]2 years ago
6 0

Answer:

Ca²⁺ + 2H⁻ + 2(2H⁺ + O²⁻) ----> Ca²⁺ + 2O²⁻ + 2H⁺ + 4H⁰

              (2 electrons lost)    ---->      (2 electrons gained)

Explanation:

The equation of the reaction is as follows: CaH₂ + 2H₂0 —> Ca(OH)₂ + 2H₂

The oxidation numbers of each of the atoms in the molecules are as follows:

In CaH₂, calcium has an oxidation number of +2, while hydrogen has an oxidation number of -1  ; Ca²⁺, 2H⁻

In 2H₂0, hydrogen has an oxidation number of +1 while oxygen has an oxidation number of -2 ; H⁺, O²⁻

In Ca(OH)₂, calcium has an oxidation number of +2 while oxygen has an oxidation number of -2 and hydrogen has an oxidation number of +1 ; Ca²⁺, O²⁻,  2H⁺

In 2H₂, each hydrogen atom has an oxidation number of 0 ; 4 H⁰

Ca²⁺ + 2H⁻ + 2(2H⁺ + O²⁻) ----> Ca²⁺ + 2O²⁻ + 2H⁺ + 4H⁰

<em>On the left hand side, the hydride ion gives up two electrons to become neutral hydrogen atoms.</em>

<em>On the right hand, two hydrogen atoms accept two electrons to form neutral atoms.</em>

<em>These neutral hydrogen atoms pair up to form two hydrogen gas molecules.</em>

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