The first one simplifies by collecting like terms to become:
7a²(4b²+9ab+10)
and the second one simplifies again by collecting like terms to become:
7u(16u²-49v²)
Got anymore questions, happy to help :)
9514 1404 393
Answer:
ACBD-BDAC
Step-by-step explanation:
It is convenient to compare the values of each of the functions when h=1. On the graphs, find 1 on the horizontal axis, then read the value of the function at that point from the vertical axis.
For the equations, the value for h=1 will be its coefficient in the equation.
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1) a: 80,b: 50, c: 75, d: 30
Fastest to slowest is ACBD.
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2) a: 4, b: 2, c: 8, d: 3
Slowest to fastest is BDAC
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The code is these lists, separated by a dash: ACBD-BDAC.
Answer:
D C
Step-by-step explanation:
first one because you do 5 to left and makes it 5 because its 1 per mile
seound one because go up 7 its at the school.
and sorry i cant see the other ones.
Step-by-step explanation:
Best is to draw a sketch of the three points.
Next step is to find the distances BC, CD, DB.
The perimeter is the sum of the three distances.
The distances are found using the distance formula:
D=sqrt((y2-y1)^2+(x2-x1)^2)
order of (x1,y1), (x2,y2) is not important.
BC=sqrt((3- -3)^2+(5-3)^2)=sqrt(6^2+2^2)=sqrt(40)=5.324
CD=sqrt((-1-3)^2+(0-5)^2)=sqrt(4^2+5^2)=sqrt(41)=6.403
DB=sqrt((-3- -1)^2+(3-0)^2)=sqrt(2^2+3^2)=sqrt(13)=3.606
So perimeter = BC+CD+DB=16.333 (approximately)
