Answer: 13 1/3
Step 1: Find the LCD
Step 2: Add the fractions
Step 3: Simplify
We know that Sum of Angles in a Triangle is Equal to 180°
Here EBF is a Triangle
⇒ m∠EBF + m∠BEF + m∠EFB = 180°
⇒ 60° + 40° + m∠EFB = 180°
⇒ 100° + m∠EFB = 180°
⇒ m∠EFB = 180° - 100°
⇒ m∠EFB = 80°
As Line m and Line p are Parallel Lines :
Alternate Interior Angles are Equal, here Alternate Interior Angles are m∠BEF and m∠ABE
⇒ m∠BEF = m∠ABE
⇒ m∠ABE = 40°
We know that Vertically Opposite Angles are Equal, Here m∠GFI and m∠EFB are Vertically Opposite Angles.
⇒ m∠GFI = m∠EFB
⇒ m∠GFI = 80°
We can notice that m∠DEB and m∠BEF form a Linear Pair
⇒ m∠DEB + m∠BEF = 180°
⇒ m∠DEB + 40° = 180°
⇒ m∠DEB = 180° - 40°
⇒ m∠DEB = 140°
We can notice that Sum of Angles m∠CBF and m∠EBF and m∠ABE is 180°
⇒ m∠CBF + m∠EBF + m∠ABE = 180°
⇒ m∠CBF + 60° + 40° = 180°
⇒ m∠CBF + 100° = 180°
⇒ m∠CBF = 180° - 100°
⇒ m∠CBF = 80°
We can notice that m∠BFG and m∠EFB form a Linear Pair
⇒ m∠BFG + m∠EFB = 180°
⇒ m∠BFG + 80° = 180°
⇒ m∠BFG = 180° - 80°
⇒ m∠BFG = 100°
We know that Vertically Opposite Angles are Equal, Here m∠BFG and m∠IFE are Vertically Opposite Angles.
⇒ m∠BFG = m∠IFE
⇒ m∠IFE = 100°
Answer:
=40/33
8/11 divide 3/5 -> 8/11 x 5/3 and multiply 8x5 then 11x3 then u got your answer! :)
Hope this worked :D
-15+9=-6 --------> -6-12=-18
15 represents where he started, then he rises upward 9 and then gets to 6. Afterwards he goes down 12 and ends up at 18 which is 3 feet lower then where he originally started.<span />
For time-speed-distance problems, you use the relationship
.. speed = distance/time
in any of its various forms.
The distance traveled at A mph is
.. distance = speed * time
.. distance = A*3
The time required for the rest of the journey is
.. time = distance / speed
.. time = (C -3A)/B
The the total time required to travel C miles is the 3 hours for the first part plus the time for the rest of the journey.
.. total journey time = 3 + (C -3A)B . . . . . hours
