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3 years ago

Write an equation in slope-intercept form for the following line: (15,-5) and (1,-7)

Mathematics

2 answers:

ella [17]3 years ago

4 0

(-14,-2)
You have to subtract the x and then the y and you get your new answer

pshichka [43]3 years ago

4 0

This is ur answer y= 1/7x - 50/7

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Which shows the following expression using positive exponents?

Hitman42 [59]

Answer:

1. option B is correct i.e., $\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. option D is correct i.e., $\frac{a^3b^4}{ab^2}$ .

3. option B is correct i.e., $\frac{n^{10}}{16m^{6}}$ .

Step-by-step explanation:

1. Since the given equation is:

$\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}$

As we know that $a^{-x}=\frac{1}{a^x}$

So, the given equation can be represented as:

$\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. Given equation is:

$\frac{a^3b^{-2}}{ab^{-4}}$

As we know that $a^{-x}=\frac{1}{a^x}$

so the given equation can be represented as:

$\frac{a^3b^4}{ab^2}$ .

3. Given equation is:

$(\frac{4mn}{m^{-2}n^6})^{-2}$

by using the properties $a^{-x}=\frac{1}{a^x}$ ,

and $a^x\times a^y=a^{x+y}$

$(\frac{4mn}{m^{-2}n^6})^{-2}$

= $(\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}$

= $(\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}$

= $(\frac{4n^{-5}}{m^{-3}})^{-2}$

= $\frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}$

= $\frac{n^{10}}{16m^{6}}$ .

which is option B.

5 0

3 years ago

Read 2 more answers

−2/3a+1/8−1/6a−3/4 PLS HELP

yarga [219]

Answer:

-5a-15/4

______

Step-by-step explanation:

8 0

3 years ago

Determine the perimeter of the following figures .

Delvig [45]

The anwser to this question would be B.:) 28

4 0

4 years ago

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What is the answer to h -13h+-38=27

riadik2000 [5.3K]

-13h + -38 = 27
You have to have all the h alone and in the same side.
-13h=65
You have to divide -13h by -13 to find one h
h = -5

3 0

4 years ago

Read 2 more answers

4 1/3 divided by 4/7 (answer using fraction)

sertanlavr [38]

Answer:

Step-by-step explanation:

Use KCF method

Keep the first fraction

Change division to multiplication

Flip the second fraction.

$4\frac{1}{3}$ ÷ $\dfrac{4}{7}$

$=\dfrac{13}{3}*\dfrac{7}{4}\\\\\\=\dfrac{91}{12}\\\\\\= 7\dfrac{7}{12}$

8 0

3 years ago