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3 years ago

Help, please! Thankyou!!!!

Mathematics

2 answers:

alukav5142 [94]3 years ago

6 0

Answer: C

Step-by-step explanation: simply apply the distributive property to each half of the expression to be left with terms that can be combined.

(8x + 16y)/2 = 4x + 8y

4(x - y) = 4x - 4y

(4x + 8y) + (4x - 4y) = 4x + 4x + 8y - 4y

= 8x + 4y => C

11111nata11111 [884]3 years ago

6 0

Answer:

$\frac{8x+16y}{2}+4(x-y)=\frac{2*4x+2*8y}{2}+4*x-4*y\\\\=\frac{2*(4x+8y)}{2}+4x-4y\\\\=4x+8y+4x-4y=8x+4y$

Step-by-step explanation:

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PLEASE HELP! 25 PTS!!

zubka84 [21]

Answer:

Solution given:

$f(x)=\frac{x-16}{x^2+6x-40}$

$g(x)=\frac{1}{x+10}$

now

f(x)+g(x)= $\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}$ ....(1)

now

factoring x²+6x-40

we get

x²+10x-4x-40

x(x+10)-4(x+10)

(x+10)(x-4)

now substituting in equation 1 ,we get

f(x)+g(x)= $\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}$

taking l.c.m

= $\frac{(x-16)+(x-4)}{(x-10)(x-4)}$

=now

opening bracket

$\frac{x-16+x-4}{x²-10x-4x+40}$

= $\frac{2x-20}{x²+6x-40}$

answer is :

B. $\bold b\frac{2x-20}{x^2+6x-40}$

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RideAnS [48]

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