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3 years ago

As electronegativity difference increases, the degree of ionic character ____ ?

Chemistry

2 answers:

Anettt [7]3 years ago

7 0

Answer: Option (a) is the correct answer.

Explanation:

When an element or atom has the ability to attract electrons towards itself then it is known that atom is electronegative in nature.

Therefore, two atoms with different electronegativity are combined together then there will be increase in electronegativity difference of the atoms.

For example, NaCl is an ionic compound.

This is because electronegative chlorine atom will attract the valence electron of sodium atom. Due to this there will be development of partial positive charge on the cation and partial negative charge on the anion. Hence, ionic character increases.

Therefore, we can conclude that as electronegativity difference increases, the degree of ionic character increases.

scoundrel [369]3 years ago

4 0

As electronegativity difference increases, the degree of ionic character increases.

The answer is increases.

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Answer:

The answer to the question is 0.0122 m/s

Explanation:

The rate of a reaction is the measure of the change in concentration of a reagent within a specific time frame. Reaction rate of a substance can be calculated by finding the division of the concentration change of the substance and the time required to undergo the change in concentration.

$Average reaction rate \frac{Change in the moles count of X}{Change in time} =$

The initial number of moles of X = 0.732 moles and final number of moles of X = 0 moles and the time it took to effect the change = 60s

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4 years ago

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2 years ago

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Answer:

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3 years ago

Diborane (B2H6) has been considered as a possible rocket fuel. Calculate DH° for the reaction B2H6(g) ---> 2B(s) + 3H2(g) usi

svlad2 [7]

Answer:

A. DH° = –36 kJ

Explanation:

It is possible to obtain DH° of a reaction by the sum of DH° of half reactions. The DH° of the reaction:

B₂H₆(g) → 2B(s) + 3H₂(g)

Could be obtained from:

(1) 2B(s) + 1.5O₂(g) → B₂O₃(s) DH° = –1273kJ

(2) B₂H₆(g) + 3O₂(g) → B₂O₃(s) + 3H₂O(g) DH° = –2035kJ

(3) H₂(g) + 0.5O₂(g) → H₂O(g) DH° = –242kJ

The sum of (2) - (1) gives:

B₂H₆(g) + 1.5O₂(g) → 2B(s) + 3H₂O(g) DH° = -2035kJ - (-1273kJ) = -762kJ

Now, this reaction - 3×(3):

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Thus, right answer is:

A. DH° = –36 kJ

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4 years ago

g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Containe

vekshin1

Answer:

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3 years ago