there you go, hope that helps
The structure that corresponds to the molecule name - 4-heptanol would be option A.
<h3>Structure of 4-heptanol</h3>
The name, 4-heptanol, indicates that there are 7 carbon atoms in the structure.
In addition, there is also an indication that there is a functional group on the 4th carbon - the alcohol functional group.
Option B has only 6 carbon atoms instead of 7. Option A, on the other hand, fulfills all the criteria.
Thus, A is the correct structure of 4-heptanol.
More on structure of compounds can be found here:brainly.com/question/8155254
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The freezing point depression is a colligative property, which means that it depends on the number of particles of solute disolved in the solution.
When you have solutes that are ionic compounds they dissociate in water into ions, then the compound that dissociates more ions will produce more particles and will decrease the freezing point the most.
Given theses aqueous solutions Na2 CO3, Co Cl3, and Li NO3 you can predict the order of the freezing points.
First, write the dissociation equations>
Na2CO3 -> 2Na(+) + CO3 (2-) These are 3 ions: two of Na(+) and one of CO3(2-)
The number inside parenthesis are number of charge not number of molecules.
Co Cl3 -> Co(3+) + 3 Cl (1-) Those are 4 ions: one of Co (+) and three of Cl (-)
Li NO3 -> Li (+) + NO3 (-) those are two ions: one of Li (+) and one of NO3(-)
Then the ionic compound that dissociates into more ions give the solution with lower freezing point, and these is the rank from higher to lower freezing point:
Li NO3 > Na2 CO3 > Co Cl3.
Answer:
Molarity of NaOH solution is 1.009 M
Explanation:
Molar mass of HCl is 36.46 g/mol
Number moles = (mass)/(molar mass)
So, 0.8115 g of HCl = 
HCl = 0.02226 moles HCl
1 mol of NaOH neutralizes 1 mol of HCl.
So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is 
So, 
or, S = 1.009
So, molarity of NaOH solution is 1.009 M
Alright! Here are the answers:
1. C. Fluorine is more reactive than nitrogen because fluorine needs only one electron to fill its outermost shell.
2. Aluminum (Al)
