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Leno4ka [110]
3 years ago
5

Diborane (B2H6) has been considered as a possible rocket fuel. Calculate DH° for the reaction B2H6(g) ---> 2B(s) + 3H2(g) usi

ng the following data: DH° (kJ) 2B(s) + 1.5O2(g) --> B2O3(s) –1273 B2H6(g) + 3O2(g) --> B2O3(s) + 3H2O(g) –2035 H2(g) + O2(g) --> H2O(g) –242 A. DH° = –36 kJ B. DH° = +36 kJ C. DH° = –86 kJ D. DH° = –86 kJ
Chemistry
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

A. DH° = –36 kJ

Explanation:

It is possible to obtain DH° of a reaction by the sum of DH° of half reactions. The DH° of the reaction:

B₂H₆(g) → 2B(s) + 3H₂(g)

Could be obtained from:

<em>(1) </em>2B(s) + 1.5O₂(g) → B₂O₃(s) DH° = –1273kJ

<em>(2) </em>B₂H₆(g) + 3O₂(g) → B₂O₃(s) + 3H₂O(g) DH° = –2035kJ

<em>(3) </em>H₂(g) + 0.5O₂(g) → H₂O(g) DH° = –242kJ

The sum of (2) - (1) gives:

B₂H₆(g) + 1.5O₂(g) → 2B(s) + 3H₂O(g) DH° = -2035kJ - (-1273kJ) = -762kJ

Now, this reaction - 3×(3):

B₂H₆(g) → 2B(s) + 3H₂(g) DH° = -762kJ - (3×-242kJ) = -36kJ

Thus, right answer is:

<em>A. DH° = –36 kJ</em>

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