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astra-53 [7]
3 years ago
11

Triangle MNO is similar to triangle PQR. If angle N measures 85 degrees and angle P measures 75 degrees, what is the measure of

angle R? 20 75 85 160
Mathematics
2 answers:
Eva8 [605]3 years ago
5 0
I think the answer is going to be 20
charle [14.2K]3 years ago
4 0

Answer:

The measure of angle R is 20°.

Step-by-step explanation:

Since, We know that,

When two triangles are similar then their corresponding angles are congruent or the measures of corresponding angles are equal,

In triangles MNO and PQR,

Angles M, N and O are corresponding to angles P, Q and R.

Given,

\triangle MNO\sim \triangle PQR

m\angle N=85^{\circ}

m\angle P=75^{\circ}

Also, By the above property,

m\angle N = m\angle Q

\implies m\angle Q = 85^{\circ}

Now, the sum of all interior angles of a triangle is supplementary,

So, in ΔPQR,

m\angle P+m\angle Q+m\angle R= 180^{\circ}

75^{\circ}+ 85^{\circ}+m\angle R= 180^{\circ}

160^{\circ}+m\angle R= 180^{\circ}

\implies m\angle R=20^{\circ}

Hence, the measure of angle R is 20°.

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4. Let c(t) be the number of customers in a department store t hours after 8 A.M. Explain the meaning
kipiarov [429]

Answer:

See explanation below.

Step-by-step explanation:

a) c(0) = 10

Here, t = 0 and c(0) = 10

At 8 A.M., there are 10 customers.

b) c(6) = c(7)

6 hours after 8 am is 2pm

7 hours after 8 am is 3pm

They are equal. So it means

There are the same number of customers at 2pm and at 3pm

c)

c(k) = 0

There are no customers, k hours after 8 am

d)

c(4) > c(3)

4 hours after 8 am is 12pm

3 hours after 8 am is 11am

This means:

The number of customers at 12pm is greater than the number of customers at 11am

4 0
3 years ago
For three consecutive numbers, the sum of the first number, twice the second and 7 less than the third is 133. What are the thre
babunello [35]

Answer:

34, 35, 36

Step-by-step explanation:

1st number = x

2nd number = x+1

3rd number = x+2

So the equation would be:

x+2(x+1)+(x+2)-7=133

x+2x+2+x+2-7=133

4x-3=133

4x=136

x=34

8 0
3 years ago
A second form of a quadratic equation is.....
k0ka [10]
Ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.
5 0
3 years ago
GEOMETRY - NEED HELP - WILL MARK BRAINLIEST
Kay [80]

Answer:

1) 51

2) 0.8

3) cosecant

Step-by-step explanation:

Question 1

The image for this scenario is attached below. Note that base of the television tower forms the side adjacent to the angle and the length of the tower forms the side opposite to the angle. The two angles marked in image are equal because of the property of Alternate Interior Angles.

So,

Adjacent side = 120 feet

Opposite side = 150 feet

Tangent of an angle is defined as:

tan(\theta)=\frac{Opposite}{Adjacent}

Using the values, we get:

tan(\theta)=\frac{150}{120}\\\\ tan(\theta)=1.25\\\\ \theta = tan^{-1}(1.25)\\\\ \theta=51.34

Rounded to the nearest degree, the angle of depression would be 51 degrees.

Question 2)

We have to find the cosine of angle Z. cos is defined as:

cos(\theta) = \frac{adjacent}{hypotenuse}

The side adjacent to angle Z is 24 and the hypotenuse is 30. So cos(Z) would be:

cos(Z)=\frac{24}{30}\\\\cos(Z)=0.8

Therefore, value of cos(Z) for given triangle would be 0.8

Question 3

The opposite of sine ratio is known as cosecant which is abbreviated as csc

Since it is the opposite of sine ratio, it would be calculated as:

csc(\theta)=\frac{1}{sin(\theta)}

sine of angle is the ratio of opposite and hypotenuse, so csc would be ratio of hypotenuse to opposite side i.e.

csc(\theta)=\frac{hypotenuse}{opposite}

5 0
3 years ago
Read 2 more answers
 If log3x – log3(x + 1) = 2log33, then x =
sergejj [24]
1)\ \ \ log_3x-log_3(x + 1) = 2log_33\ \ \ \Rightarrow\ \ \ D:x>0\ \ \ and\ \ \ x+1>0\\. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=(0;+\infty)\\\\log_3 \frac{x}{x+1} =log_33^2\ \ \ \Leftrightarrow\ \ \ \ \frac{x}{x+1}=9\ /\cdot(x+1)\\\\x=9(x+1)\\\\x=9x+9\\\\-8x=9\ \ \ \Leftrightarrow\ \ \ x=- \frac{9}{8} \ \notin\ D\ \ \ \Rightarrow\ \ \ no\ solution\\\\

2)\ \ \ log3x-log3(x + 1) = 2log33\ \ \ \Rightarrow\ \ \ D:x>0\ \ \ and\ \ \ x+1>0\\. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=(0;+\infty)\\\\log \frac{3x}{3(x+1)} =log33^2\ \ \ \Leftrightarrow\ \ \  \frac{x}{(x+1)} =1089\ /\cdot(x+1)\\\\x=1089(x+1)\\\\x=1089x+1089\\\\x-1089x=1089\\\\-1088x=1089\ /:(-1088)\\\\x=- \frac{1089}{1088} \ \notin\ D\ \ \ \Rightarrow\ \ \ no\ solution\\\\Ans.\ the\ equation\ has\ no\ solution.
4 0
3 years ago
Read 2 more answers
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