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SIZIF [17.4K]
3 years ago
15

3^x+2=8^x-1 Solve for x.

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

I assume the equation is supposed to be

3^{x+2}=8^{x-1}

Then we can write

9\cdot3^x=\dfrac18\cdot8^x\implies\left(\dfrac38\right)^x=\dfrac1{72}

Take the logarithm of base 3/8 on both sides:

\log_{3/8}\left(\dfrac38\right)^x=\log_{3/8}\dfrac1{72}

\implies x\log_{3/8}\dfrac38=-\log_{3/8}72

\implies x=-\log_{3/8}72

- - -

If the equation is actually 3^x+2=8^x-1, I'm afraid it cannot be solved exactly.

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