The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib

For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer:
Step-by-step explanation:
Thx for the points
Answer:
<h3>11.8 feet</h3>
Step-by-step explanation:
Given
Length of the ladder = 12foot
angle of elevation = 80 degrees
Required
Height of the wall (opposite side)
The set up will form a right angled triangle where
length of the ladder is the hypotenuse
height of the wall is opposite;
Using SOH, CAH, TOA trig identity
According to SOH
sin 80 = opp/hyp
sin80 = opp/12
opp = 12sin80
opp = 11.82 feet
Hence the height of the wall is 11.8feet (to the nearest tenth)
5 (x+4) ...................