The answer is A. You can solve this by plugging the X values from the table into the equation and seeing if you end up with the right Y value.
Step-by-step explanation:
f(x)=2x-7.
by substituting value 0 for x,
f (0)=2×0-7
f (0)=-7
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: hourly wage of a high school student
X~N(μ;σ²)
X[bar]= $8.25
σ= $0.25
For a 95% CI for the average hourly wage for<u> 1 </u>high school student:
For this exercise you have to consider the sample size n=1
a) The margin of error of the CI is calculated as:
d=
* σ
1-α: 0.95 ⇒ α:0.05
1-α/2:0.975

d= 1.96 * 0.25= 0.49
b)
The formula for the interval is
X[bar] ±
* σ
[8.25 ± 0.49]
[7.76; 8.74]
With a 95% you'd expect the interval $[7.76; 8.74] to include the average hourly wage of one high school student in Illinois.
c)
Te calculated interval is $ [7.76; 8.74] the value $9.15 does nor fall within that acceptable range.
I hope this helps!
It's 38,000. Always try to remember that anything below 500 rounds down, anything higher then 500 would go to the next thousand. For example, of that number would of been 38,555 the number would be 39,000.
Answer:
I think reflected then rotated clockwise on around center h at 60 degrees
Step-by-step explanation:
Im almost sure about this but this was confusing