So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
The answer is 3
Step-by-step explanation:
If a/b = 2, then b/a = 1/2
Now,
6b/a = 6 × 1/2 = 6/2 = 3
Thus, The answer is 3
<u>-TheUnknownScientist</u><u> 72</u>
<h2>
Answer:CAN YOU PLEASE HELP ME!!????</h2>
Step-by-step explanation:What percent is represented by the diagram below?
Alternative text
A. 13%
B. 65%
C. 130%
<h3>
D. 650%</h3>
.21 is decimal form, 21/100 is the fraction in simplest form.