Answer:
0.01024
Step-by-step explanation:
Assume marking was done at random : Hence, each of the 5 time slots have equal Chamves of being marked ;
Number of time slots, n = 5
Required to mark, number of preferred timeslot x = 2
P(x) = 2 /5 = 0.4
Probability of 0.4 that an interviewee gets one of his preferred timeslot.
Probability that each of the 5 interviewees gets one of their preferred time slots :
Using the multiplication rule of independence :
0.4 * 0.4 * 0.4 * 0.4 * 0.4 = 0.4^5 = 0.01024
0.01024 * 100% = 1.024%
<span><span>1.
If we get an odd number first (probability 5/10 = 1/2), then the only way to get a number greater than 9 is the 10 (probability 1/9, since only 9 papers remain). This gives 1/2 * 1/9 = 1/18.</span></span><span><span>
</span></span><span><span>
</span></span><span><span>2.
We would expect that P(2 white cards) = P(1 white card)*P(2nd white card given 1 white card).</span></span><span><span /></span><span><span>This gives the equation 14/95 = 2/5 * x<span>
</span></span></span><span><span><span>Solving for x gives x = 7/19.</span></span></span><span><span>
</span></span><span><span>
</span></span><span><span>3. There are a total of 4 favorable results: 1, 4, 5, 6. Out of the 6 possibilities, this is a probability of 4/6 = 2/3.</span></span>
Answer:
The answer is 2.55
Step-by-step explanation:
As a fraction:
5 6/10
560/100
5 3/5
as a decimal:
5.6
5.6000
Answer:
QRP
Q = 8x-10
R = 7x+6
P = 7x+8
Step-by-step explanation:
Let x be any positive integer, say x=2
P=7x+8=(7*2)+8=22 units
Q=8x-10=(8*2)-10=6 units
R=7x+6=(7*2)+6=20 units
From the above, Q is the shortest and P is the longest side. Therefore, the sides arranged from shortest to longest will be Q, R, P
