Answer: 0.25 m/s
Explanation: Speed = wavelengt · frequency
v = λf and frequency is 1/period f = 1/T
Then v = λ/T = 5 m / 20 s = 0.25 m/s
The spin quantum number is represented by the symbol m s a nd has the possible values +1/2.-1/ corresponding to the two directions of the electron's magnetic field.
The magnetic quantum quantity tells us what number of orbitals there are in a subshell and the feasible orientations of those orbitals. Its value is dependent on the angular momentum quantum range.
The magnetic discipline is an area in area close to a magnet or an electric contemporary wherein a physical area is produced from a shifting electric rate that creates force on some other shifting electric rate. An instance of a magnetic field is the Earth's magnetic
All magnets have north and south poles. contrary poles are drawn to every other, whilst the identical poles repel each different. when you rub a chunk of iron alongside a magnet, the north-in search of poles of the atoms in the iron line up inside the identical route. The force generated by using the aligned atoms creates a magnetic subject.
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An atom gains one or more electrons and becomes negatively charged, or loses one or more electrons and becomes positively charged.
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
= 
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
