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2 years ago

Need thy help once again

Physics

1 answer:

Thepotemich [5.8K]2 years ago

8 0

B cause I took the quiz

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Which state helps produce light in fluorescent light bulbs?

spin [16.1K]

The answer is D plasma

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3 years ago

A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î

Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value $\vec{v}\times\vec{B}$

$(\vec{v}\times\vec{B})=3i+4j+11k$

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

$\vec{F}=q(\vec{v}\times\vec{B})$

Put the value into the formula

$\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)$

$\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}$

$|F|=2.6\times10^{-9}\ N$

Hence, The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

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2 years ago

With the switch closed, how does the voltage across the 20-ω resistor compare to the voltage across the 10-ω resistor?

jasenka [17]

In electricity, the most famous and basic equation is the Ohm's Law which relates the parameters voltage, current and resistance. One form of this law as written in equation is V = IR, where V is the voltage in volts, I is the current in amperes and R is the resistance in ohms. These parameters depends in the arrangements, whether it's series or parallel.

In a series connection, the voltage is greater across a high-resistance resistor. Therefore, the voltage is much greater for the 20-ohm resistor. However,if it is a parallel circuit, the voltage is just the same for both resistors.

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3 years ago

Suppose a 1300 kg car is traveling around a circular curve in a road at a constant

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Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :

$F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N$

So, the force has a magnitude of 4212 N

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2 years ago

A device for exercising the upper leg muscle is shown above, together with a schematic representation of an equivalent lever sys

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2 years ago