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k0ka [10]
3 years ago
8

A uniform electric field is pointing in x direction. The magnitude of the electric field is 10 N/C. The filed makes an angle of

30 deg with a rectangular surface of area 2 x10 m Calculate the electric flux crossing the surface.
Physics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

- 100 Nm²/C

Explanation:

E = magnitude of electric field along x-direction = 10 N/C

θ = angle made by the direction of electric field with rectangular surface = 30

φ = angle made by the direction of electric field with normal to the rectangular surface = 90 + 30 = 120

A = area of the rectangular surface = 2 x 10 = 20 m²

Φ = Electric flux crossing the surface

Electric flux is given as

Φ = E A Cosφ

Φ = (10) (20) Cos120

Φ = - 100 Nm²/C

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