Answer:
The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.
Down to the left, down the the right, criss cross!
To convert 3 miles per hour into m/s, first we have to convert miles in to meter and then hour in to second.
As 
and
Therefore,
Answer:
The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N
Explanation:
Forces on block 4.3 kg are:
63N to the right and R21 (contact force from the 6.3 kg block) to the left
Net force on 4.3 kg block is: 63 N - R21
Forces on the 6.3 kg block are:
R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.
So net force on the 6.3 kg block is: R12 - 11 N
According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").
Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:
a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2
solve for R by cross multiplication
6.3 (63 - R) = 4.3 (R - 11)
396.9 - 6.3 R = 4.3 R - 47.3
369.9 + 47.3 = 10.6 R
444.2 = 10.6 R
R = 444.2 / 10.6
R = 41.90 N
Answer:
R = ½ R₀
Explanation:
This is an exercise in Ohm's law,
V = IR
in the initial case
V₀ = I₀ R₀ (1)
indicates that the voltage remains constant and the current is doubled
I = 2 I₀
V₀ = I R
we substitute
V₀ = 2 I₀ R
R = ½ V₀ / I₀
we replace by equation 1
R = ½ R₀
