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3 years ago

What is the base metric unit for measuring mass?

Physics

2 answers:

omeli [17]3 years ago

7 0

The basic metric unit for mass in the kilogram

Zanzabum3 years ago

4 0

Metric system uses units such as meter, liter and gram to measure the length, volume and mass of a particular object. The metric system is based on 10s unlike the US Customary system of measurement which uses foot, yard and mile. So, for the base metric unit for measuring mass, the answer would be gram or kilogram.

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A cook preparing a meal for a group of people is an example of ______

Sati [7]

Answer:

Option B is correct.

Explanation:

Potential energy or chemical potential energy is used to Cook food which is then converted into thermal energy. The type of energy used also depends upon the type of cooking appliances used.

For e.g. stove convert potential energy to thermal energy.

7 0

4 years ago

PLZ HELP ME ITS MY LAST QUESTION I GOT LIKE 6 MIN LEFT

spin [16.1K]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver = 77kg

Height = 8.18m

Unknown:

Speed of the diver before hitting the water = ?

Solution:

The speed of the diver before hitting the water is the final velocity.

To solve this problem, we use the expression below;

v² = u² + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

Now insert the parameters and solve;

v² = 0² + 2 x 9.8 x 8.18

v² = 160.328

v = 12.7m/s

3 0

3 years ago

A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due

Korvikt [17]

Answer:

$\Phi_E=0.11\frac{N\cdot m^2}{C}$

Explanation:

According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of the spherical surface:

$\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}$

This is identical to the electric flux of a point charge located in the center of the sphere.

$\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}$

8 0

4 years ago

There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of

Cerrena [4.2K]

Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

$2gh = V_{f}^2 - V_{i}^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

$(2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\$

8 0

3 years ago

The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect

Advocard [28]

<h3><u>Answer;</u></h3>

Doubles and Remains the same

<h3><u>Explanation;</u></h3>

The effect of doubling the absolute temperature of a sample of a monoatomic ideal gas is that,the pressure doubles and density of the sample of gas remains the same.
<em><u>According to ideal gas equation; PV = nRT; Where P is pressure and V is the Volume, n is the number of moles, R is the ideal gas constant and T is the absolute temperature.</u></em>
<em><u>Therefore, when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.</u></em>
However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.

5 0

3 years ago