<u>Answer:</u>
This figure shows the Second Kepler’s Law of Planetary Motion, <em>The line that joins the planet with the Sun sweeps equal areas in equal times</em>.
According to this statement, the only way in which this is fulfilled is that the planet moves faster when it is <u>near the sun (perihelion)</u> and moves slower when it is <u>far from the Sun (aphelion</u>).
In the image shown, if points W and X are at the same distance to the Sun, this means the instantaneous velocity of the planet in both points is the same.
<span> A pure substance is an material which contains atoms of only one kind.
It has fixed physical and chemical properties such as boiling point, melting point, valency, density and more.</span>
Answer:
Option (D) is correct.
Explanation:
The balloon lands horizontally at a distance of 420 m from a point where it as released.
Velocity of air balloon along +X axis =10 m/s
velocity of ball=4 m/s along + X axis
the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s
time taken= 30 s
The distance traveled is given by d= v t
d= 14 (30)
d= 420 m
Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.
Answer: The De broglie's wavelength is 1.45×10^-14m
Explanation:
Using De broglie's equation
λ= h/mv
Where h= Planck's constant = 6.6×10^-34Js
m= mass in kilogram = 3.8×10^-28kg
V= velocity = acceleration ×time =
2.4×10^7 ×5
V= 1.2×10^8m/s
λ= is the De broglie's wavelength
λ= 6.6×10^-34Js /(3.8×10^-28kg ×1.2×10^8)
λ= 1.45×10^-14m
Therefore ,De broglie's wavelength=
1.45×10^-14m
Answer:
2y
Explanation:
Electric field in terms of Electric potential is given as:
E = dV/dr(x, y, z)
Where r(x, y, z) = position in x, y, z plane
The y component of the Electric field will be:
Ey = -dV/dy
Given that
V = 2x - y² - cos(z)
dV/dy = -2y
=> E = - (-2y)
E = 2y
