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densk [106]
3 years ago
15

PLZ HELP ME ITS MY LAST QUESTION I GOT LIKE 6 MIN LEFT

Physics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver  = 77kg

Height  = 8.18m

Unknown:

Speed of the diver before hitting the water = ?

Solution:

The speed of the diver before hitting the water is the final velocity.

       To solve this problem, we use the expression below;

       v² = u²  + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

  Now insert the parameters and solve;

     

 v²   = 0²   + 2 x 9.8 x 8.18

 v²   = 160.328

  v  = 12.7m/s

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The free length of the spring that is attached to the 0.3-lb slider is 3 in. If the slider is released from rest when x = 6 in.,
hichkok12 [17]

Answer:

a = 64 ft / s²

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Reduscate to the English system

          x = 3 in (1foot/12 in) =0.25 foot

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        a = 64 ft / s²

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