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3 years ago

10

0.30 s after seeing a puff of smoke rise from the starter pistol the sound of the firing of the pistol is heard by the track tim

e by a 100m away. What is the speed of sound

1 answer:

Paraphin [41]3 years ago

3 0

The speed of sound is 100 divided by 0.30
So that makes it 333.333333333333 second per meter

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3 years ago

an 0.45-kg object is being pulled with a tension force of 14.2 n at a constant velocity of 3.41 m/s. what is the force of fricti

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The forces of friction acting on the object are <u>12.67 N.</u>

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ma - 14.2 N = Friction force

14.2 N - 0.45 × 3.41 = <u>12.67 N</u>

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1 year ago

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3 years ago

Read 2 more answers

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3 years ago

A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft

Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

$m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s$

Using the equation to find $v_1$ ,

$v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475$

Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

$KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J$

$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

$92708.9=\frac{1}{2}15.5v_2^2$

$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

4 0

3 years ago