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77julia77 [94]
3 years ago
5

all of the following answer choices are ideas from daltons atomic theory. which one of them do we now know is not true?

Physics
1 answer:
dem82 [27]3 years ago
5 0
Did you forget to include the options?
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if the train is accelerating and the bisicle is traveling at a constant velocity, what do you know about their speed?
Vanyuwa [196]
The train is accelerating meaning there is a change in the velocity so the speed is either increasing or decreasing depending. The bicycle is travelling at a constant velocity meaning it is travelling at a constant speed.
3 0
3 years ago
A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a
EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2} (1)

Where:

p_{S,1}, p_{S,2} - Initial and final momemtums of the small object, measured in kilogram-meters per second.

p_{B,1}, p_{B,2} - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that p_{S,1} = 7\,\frac{kg\cdot m}{s}, p_{B,1} = 0\,\frac{kg\cdot m}{s} and p_{S, 2} = 4\,\frac{kg\cdot m}{s}, then the final momentum of the big object is:

7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}

p_{B,2} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is:

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

4 0
2 years ago
A 2 kg block is on a horizontal surface. A horizontal force is applied by a person to the block to pull it on the surface with a
Agata [3.3K]

Answer:

work done = 500 J

option e is correct

Explanation:

given data

mass = 2 kg

acceleration = 2 m/s

coefficient of kinetic friction = 0.3

block D = 50 m

to find out

work

solution

we know that work done is

work done = f × d    ...........1

here f is force and d is block i.e 50 m

so here

force , f - k mg  =ma

f = 2 ( 2 + 0.3 ×10 )

f = 10 N

so from equation 1

work done =  f × d

work done = 10 × 50

work done = 500 J

option e is correct

3 0
3 years ago
How does a pie chart help form conclusion
daser333 [38]

Its easy to create a visual and see major differences between data. If something takes up a large portion of the pie, its easy for you to tell just by looking at it
3 0
3 years ago
How much energy is needed to raise the temperature of a 55g sample of aluminum from 22.4 to 94.6?
BaLLatris [955]
The heat needed is given by Mcθ , where m is the mass in Kg, c is the heat capacity of aluminium, and θ is the change in temperature. 
Specific heat capacity of aluminium is 0.9 j/g°c
thus; Heat = 55 × 0.9 × 72.2
                 = 3573.9 Joules or 3.574 kJ
3 0
3 years ago
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