Recall the examples of transmission and absorption, then determine which ones are similar here.
2 answers:
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Answer:
x = 11.23 m
Explanation:
For this interesting exercise, we must use angular kinematics, linear kinematics and the relationship between angular and linear quantities.
Let's reduce to SI system units
θ = 155 rev (2pi rad / rev) = 310π rad
α = 2.00rev / s2 (2pi rad / 1 rev) = 4π rad / s²
Let's look for the angular velocity at the time the piece is released, with starting from rest the initial angular velocity is zero (wo = 0)
w² = w₀² + 2 α θ
w =√ 2 α θ
w = √(2 4pi 310pi)
w = 156.45 rad / s
The relationship between angular and linear velocity
v = w r
v = 156.45 0.175
v = 27.38 m / s
In this part we have the linear speed and the height that it travels to reach the floor, so with the projectile launch equations we can find the time it takes to arrive
y = t - ½ g t²
As it leaves the highest point its speed is horizontal
y = 0 - ½ g t²
t = √ (-2y / g)
t = √ (-2 (-0.820) /9.8)
t = 0.41 s
With this time we calculate the horizontal distance, because the constant horizontal speed
x = vox t
x = 27.38 0.41
x = 11.23 m
Explanation:
(a) It is known that equation for transverse wave is given as follows.
y =
Now, we will compare above equation with the standard form of transeverse wave equation,
y =
where, A is the amplitude = 0.09 m
k is the wave vector =
is the angular frequency =
x is displacement = 1.40 m
t is the time = 0.16 s
Now, we will differentiate the equation with respect to t as follows.
The speed of the wave will be:
v(t) =
v(t) =
v(t) =
v(t) = -0.84 m/s
The acceleration of the particle in the location is
a(t) =
a(t) =
a(t) =
a(t) = -9.49
Hence, the value of transverse wave is 0.84 m/s and the value of acceleration is 9.49
.
(b) Wavelength of the wave is given as follows.
= 22 m
The period of the wave is
T =
T =
= 0.5 sec
Now, we will calculate the speed of propagation of wave as follows.
v =
=
= 44 m/s
therefore, we can conclude that wavelength is 22 m, period is 0.5 sec, and speed of propagation of wave is 44 m/s.