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vovikov84 [41]
3 years ago
15

How many cubs can a panda have at once and how long does it take for a mother panda to give birth?

Physics
2 answers:
SVEN [57.7K]3 years ago
7 0
I believe that pandas can only have 1 cub at a time. (Online it says 1.5 cubs but I’m not quite sure how half a cub would work) Their gestation period (how long it takes them to have their cub) is 3-5 months. This is for a giant panda.
nevsk [136]3 years ago
5 0

Answer:

it take 2 years until she give birth and thay only get a cub twice a year have a good day

Explanation:

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Plants appear green because they do not absorb the green wavelengths of light what happens to those green light waves when they
Arlecino [84]
The green wavelengths are reflected, causing green to be the only color we see in certain parts of plants.

Best of luck, my man.
4 0
3 years ago
Read 2 more answers
What is the meaning of lightyear?
puteri [66]
"Lightyear" is a <em>distance</em> ... specifically, the distance that light travels
through vacuum in one year of 365 days.

It's equivalent to  9.454 x 10^12 kilometers, or  5.875 x 10^12 miles . 
7 0
3 years ago
A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

We know that,

m_{p}c^2=m_{np}c^2

So, E_{photon}=2mc^2+K.E_{p}+K.E_{np}

K.E_{np}=E_{photon}-(2mc^2+K.E_{p})

Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0
3 years ago
A normal blood pressure reading is less than 120/80 where both numbers are gauge pressures measured in millimeters of mercury (m
KIM [24]

The pressure value is given by the equation,

P= \rho gh

Where,

\rho represents the density of the liquid

g= gravity

h= Heigth

A) For the measurement of the guage pressure we have the data data,

\rho_{mercury} = 13.6*10^3kg/m^3

h=0.0930m

g=9.8m/s^2

Replacing we get,

P_g=\rho_{mercury}gh

[tex]P_g = (13.6*10^3)(9.8)(0.0930)P_g = 12395Pa[/tex]

In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,

B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

P_T = P_a+P_g\\P_T = 101325Pa+12395Pa\\P_T = 113720Pa\\P_T = 113.7kPa

6 0
3 years ago
An object is (starting at rest) begins to plummet towards the earth. Assuming it is in a vacuum, how fast is the object travelin
Eva8 [605]

Answer:

–50.96

Explanation:

The following data were obtained from the question:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =

a = (Vբ – Vᵢ) / t

With the above formula, we can determine how fast the object is traveling after 5 s as follow:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

a = (Vբ – Vᵢ) / t

– 9.8 = (Vբ – 0) / 5.2

– 9.8 = Vբ / 5.2

Cross multiply

Vբ = –9.8 × 5.2

Vբ = –50.96 m/s

Therefore, the object is traveling at

–50.96 m/s

8 0
3 years ago
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