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3 years ago

Distinguish between the key features of Charles's Law and

Physics

1 answer:

Alborosie3 years ago

7 0

Answer:

The answer is below

Explanation:

Charles law states that the volume and temperature of a fixed amount of a gas is directly proportional to each other provided that pressure is held constant.

Boyle's law states that the volume and pressure of a fixed amount of a gas are inversely proportional to each other provided that temperature is held constant.

a) Constant property:

In Charles law, pressure is kept constant while in Boyle's law, temperature is held constant.

b) Varying properties:

In Charles law, volume and temperature are varying while in Boyle's law, pressure and volume are varying.

c) Type of variance:

In Charles law we have a direct variance while in Boyle's law we have an indirect variance.

d) Charles law is given as:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Boyle's law is given as:

$P_1V_1=P_2V_2$

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A runner runs a 1,500 m race on a circular track. The runner stops 100 m from the starting point. What are the distance and disp

viva [34]

Answer:

distance- 1400 m

displacement- 100 m before the finish line

Explanation:

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3 years ago

According to Archimedes’ principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this

Andrew [12]

Answer:

Part a)

$\rho = 0.55 g/cm^3$

Part b)

$\rho_L = 1.49 g/cm^3$

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

Explanation:

Part a)

As we know that when cylinder float in the water then weight of the cylinder is counter balanced by the buoyancy force

So here we know

buoyancy force is given as

$F_b = \rho_w V_{sub} g$

$F_b = (1 g/cm^3) (30 - 13.5) Ag$

$F_b = 16.5 Ag$

Now we know that the weight of the cylinder is given as

$W = \rho (30 cm)A g$

now we have

$\rho (30 cm) A g = 16.5 A g$

$\rho = 0.55 g/cm^3$

Part b)

When the same cylinder is floating in other liquid then we will have

$F_b = \rho_L (30 - 18.9 )A g$

so we have

$\rho_L (11.1) Ag = 0.55(30) Ag$

$\rho_L = 1.49 g/cm^3$

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

3 0

3 years ago

3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin

Alex787 [66]

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2