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3 years ago

Distinguish between the key features of Charles's Law and

Physics

1 answer:

Alborosie3 years ago

7 0

Answer:

The answer is below

Explanation:

Charles law states that the volume and temperature of a fixed amount of a gas is directly proportional to each other provided that pressure is held constant.

Boyle's law states that the volume and pressure of a fixed amount of a gas are inversely proportional to each other provided that temperature is held constant.

a) Constant property:

In Charles law, pressure is kept constant while in Boyle's law, temperature is held constant.

b) Varying properties:

In Charles law, volume and temperature are varying while in Boyle's law, pressure and volume are varying.

c) Type of variance:

In Charles law we have a direct variance while in Boyle's law we have an indirect variance.

d) Charles law is given as:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Boyle's law is given as:

$P_1V_1=P_2V_2$

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Luba_88 [7]

Answer: Option (b) is the correct answer.

Explanation:

It is given that a positive test charge q is released from rest at a distance r away from a charge of +Q and a distance 2r which is away from a charge of +2Q.

Then test charge to the right immediately after being released.

Therefore, the net force will be as follows.

F = $\frac{kqQ}{r^{2}} - kq\frac{(2Q)}{(2r)^{2}}$

= $\frac{4KqQ - 2KqQ}{4r^{2}}$

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A stone is tied to a 0.85-meter cord. it is swung in a circle at a constant rate of 6.0 m/s. what is the centripetal acceleratio

Andrei [34K]

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Explanation:

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Two wheels are identical but wheel b is spinning with twice the angular speed of wheel

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3 years ago

A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from

Ulleksa [173]

Answer:

$1270.64\ \text{J}$

Explanation:

m = Mass of object = $\dfrac{mg}{g}$

mg = Weight of object = 20 N

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

$\theta$ = Angle of slope = $30^{\circ}$

f = Force of friction

fd = Work done against friction

The force balance of the system is

$\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}$

The work done against friction is $1270.64\ \text{J}$ .

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