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ratelena [41]
2 years ago
12

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

f 0.6 meters?
5.52 × 102 hertz
2.56 × 102 hertz
459 × 102 hertz
675 × 102 hertz
990 × 102 hertz
Physics
1 answer:
tatiyna2 years ago
7 0

Answer:

5.52 \cdot 10^2 Hz

Explanation:

For a wave, the relationship between velocity, wavelength and frequency is given by the wave equation:

v=f\lambda

where

v is the velocity

f is the frequency

\lambda is the wavelength

For the sound wave in this problem, we have:

v = 331 m/s

\lambda=0.6 m

Solving the equation for f, we find the frequency:

f=\frac{v}{\lambda}=\frac{331}{0.6}=5.52\cdot 10^2 Hz

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Answer:

Option D

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The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

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A copper telephone wire has essentially
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Answer:

128.21 m

Explanation:

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Initial temperature (θ₁) = 4 °C

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Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

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If a circuit has a power of 50 W with a current of 4.5 A, what is the resistance in the circuit?
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D

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