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ratelena [41]
3 years ago
12

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

f 0.6 meters?
5.52 × 102 hertz
2.56 × 102 hertz
459 × 102 hertz
675 × 102 hertz
990 × 102 hertz
Physics
1 answer:
tatiyna3 years ago
7 0

Answer:

5.52 \cdot 10^2 Hz

Explanation:

For a wave, the relationship between velocity, wavelength and frequency is given by the wave equation:

v=f\lambda

where

v is the velocity

f is the frequency

\lambda is the wavelength

For the sound wave in this problem, we have:

v = 331 m/s

\lambda=0.6 m

Solving the equation for f, we find the frequency:

f=\frac{v}{\lambda}=\frac{331}{0.6}=5.52\cdot 10^2 Hz

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Cloud [144]

(a) The free body of all the forces include, frictional force, weight of the box acting perpendicular and another acting parallel to the plane.

(b) When the box is sliding down, the frictional force acts towards the right.

(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

<h3>Free body diagram</h3>

The free body diagram of all the forces on the box is obtained by noting the upward force and downward forces on the box as shown below;

                      /  W2

                    Ф → Ff

                    ↓W1

where;

  • Ff is the frictional force resisting the down motion of the box
  • W1 is the perpendicular component of the box weight = Wcos(33)
  • W2 is the parallel component of the box weight = Wsin(33)

(b) When the box is sliding down, the frictional force acts towards the right.

(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

Learn more about free body diagram of inclined objects here: brainly.com/question/4176810

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