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Lemur [1.5K]
3 years ago
13

can someone go to my profile then go to my questions I keep posting them but no one replies please I need help

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Answer:

ok ill look

Step-by-step explanation:

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An 8-meter roll of blue ribbon costs $5.12. What is the unit price?<br> per meter<br> Submit
ivann1987 [24]

Answer:

$0.64

Step-by-step explanation:

Unit price is the cost of a single metre of ribbon

5.12/8=0.64

7 0
3 years ago
So if you need 30 bags but you can buy 200 bags for 6.19 how much does it cost for 1 bag?​
maw [93]

Answer:

0.03095

Step-by-step explanation:

         0.03095

200   6.19000

        -600

           1900

          -1800

             1000

            -1000

             0

4 0
2 years ago
A staff gauge measures the height of the water level in a river compared to the average water level. At one gauge the river is 1
Juli2301 [7.4K]

The river will not reach a level of 7 ft. after 5 hours.

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let y represent the height of the water level after x hours.

Since the  river is 1 ft below its average water level and  begins to rise by a constant rate of 1.5 ft per hour. Hence:

b = -1, m = 1.5. The equation becomes:

y = 1.5x - 1

To reach a level of 7 ft. That is y = 7:

7 = 1.5x - 1

1.5x = 8

x = 5.3 hours

The river will not reach a level of 7 ft. after 5 hours.

Find out more at: brainly.com/question/13911928

5 0
2 years ago
Find the decay factor from the equation y = 453(0.87)^4
dybincka [34]

The decay factor of the equation given in the task content is; 0.87.

<h3>What is the decay factor from the equation?</h3>

According to the task content; the equation given is; y = 453(0.87)^4.

By comparison with exponential decay functions, it follows that the decay factor from the equation given is; 0.87 which insinuates that the factor of change after each decay is 0.87.

Read more on decay factor;

brainly.com/question/1522819

#SPJ1

7 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2.
Paul [167]

Answer:

D. y = one divided by eightx2

Step-by-step explanation:

The standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2 is y = one divided by eightx2.

3 0
3 years ago
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