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Anon25 [30]
3 years ago
7

A cannonball is launched at ground level at an angle of 30° above the horizontal with

Physics
2 answers:
user100 [1]3 years ago
8 0

Answer:

use the kinematics equations and solve for time, after that use dleta dx=Vi*delta time

Nookie1986 [14]3 years ago
8 0
Use the kemetic equation
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5. Which of the following is NOT a course goal?
kifflom [539]

Answer:

for students to do nothing

Explanation:

because doing nothing is not a course goal

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3 years ago
When an electron loses or gains a charge, it becomes?​
suter [353]

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It becomes an Ion with either positive or negative charge

6 0
2 years ago
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The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m
IgorC [24]

Answer:

0.0360531138247 V/m

Explanation:

\rho = Resistivity of gold = 2.44\times 10^{-8}\ \Omega .m (General value)

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A = Area = \dfrac{\pi}{4}d^2

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\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m

The  electric field in the wire is 0.0360531138247 V/m

6 0
3 years ago
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Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight dow
bulgar [2K]

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

F=\frac{\Delta p}{\Delta t}

where

F is the force exerted

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be rewritten as

\Delta p = m(v-u)

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

F=\frac{m(v-u)}{\Delta t}

In this problem we have:

\frac{m}{\Delta t}=0.030 kg/s is the mass rate

u=-15 m/s is the initial velocity

v=+15 m/s is the final velocity

Therefore, the force exerted by the hail on the roof is:

F=(0.030)(+15-(-15))=0.9 N

6 0
3 years ago
If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be
Vlad1618 [11]
<span>Usually, If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, the statement which would best describe what would occur is the last one : </span><span>The water and the metal's temperatures will reach the same temperature. I choose this one because this is a nice example of how the nature tries to reach the balance. Hope it helps! Regards.</span>
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3 years ago
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