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Tema [17]
3 years ago
15

Suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.

4 solar mass limit? suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.4 solar mass limit? the white dwarf will collapse to become a black hole. the white dwarf will undergo a nova explosion. the white dwarf will collapse in size, becoming a neutron star. the white dwarf will explode completely as a white dwarf supernova.
Physics
2 answers:
lukranit [14]3 years ago
8 0

Answer:

The white dwarf will explode completely as a white dwarf supernova.

Explanation:

When a white dwarf gains mass to the Chandrasekhar limit of 1.44 solar masses, it would begin to collapse and, in a few seconds, the matter in the white dwarf will undergo nuclear fusion, and will become in a supernova.  

Only when the core of the white dwarf is composed of neon, magnesium, and oxygen, the gaining mass to 1.44 solar mass, will result in a neutron star.      

Therefore, the answer is the white dwarf will explode completely as a white dwarf supernova.              

I hope it helps you!                

Soloha48 [4]3 years ago
7 0
It would blow up turning into a supernova.
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Calculate the work done when a 100-W lightbulb is lit for 30 seconds.
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Answer:

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8 0
3 years ago
On Earth, 1 kg = 9.8 N = 2.2 lbs. On the Moon, 1 kg = 1.6 N = 0.37 lbs. Use these relationships to answer the following question
romanna [79]

Answer:

(a) 490 N on earth

(b) 80 N on earth

(c) 45.4545 kg on earth

(d) 270.27 kg on moon

Explanation:

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And 1 kg = 1.6 N = 0.37 lbs on moon

(a) We have given mass of the person m = 50 kg

As it is given that 1 kg = 9.8 N

So 50 kg = 50×9.8 =490 N

(b) Mass of the person on moon = 50 kg

As it is given that on moon 1 kg = 1.6 N

So 50 kg = 50×1.6 = 80 N

(c) We have given that weight of the person on the earth = 100 lbs

As it is given that 1 kg = 2.2 lbs on earth

So 100 lbs = 45.4545 kg

(d) We have given weight of the person on moon = 100 lbs

As it is given that 1 kg = 0.37 lbs

So 100 lbs \frac{100}{0.37}=270.27kg

8 0
3 years ago
An engine is used to lift a beam weighing 9,800 N up to 145 m. How much work must the engine do to lift this beam? How much work
Arturiano [62]

Explanation:

Given that,

Weight of the engine used to lift a beam, W = 9800 N

Distance, d = 145 m

Work done by the engine to lift the beam is given by :

W = F d

W=9800\ N\times 145\ m\\\\W=1421000\ J\\\\W=1421\ kJ

Let W' is the work must be done to lift it 290 m. It is given by :

W'=9800\ N\times 290\ m\\\\W'=2842000\ J\\\\W'=2842\ kJ

Hence, this is the required solution.

5 0
3 years ago
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