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WITCHER [35]
3 years ago
5

What will happen two temperatures if you increase particle motion

Physics
1 answer:
nalin [4]3 years ago
8 0

If the temperature is increased the particles gain more kinetic energy or vibrate faster. This means that they move faster and take more space.

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What can we say about energy on
Marina CMI [18]

Answer:

A. Longer wavelengths and less dangers

Explanation:

Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;

Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.

8 0
3 years ago
A metal ball has a mass of 2kg and a volume of 6 m3. What is its density
Lena [83]

Answer: The answer is 333.3333 repeating

Explanation:

Divide the mass by the volume.

8 0
3 years ago
Read 2 more answers
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
A bicyclist travels at 15 miles per hour south. After 10 minutes, the cyclist is traveling at 20 miles per hour south. Which is
denpristay [2]
<span>By adding "south", the speed had both magnitude AND direction, becoming a vector, not a scalar which generic "speed" is. So the second option can be eliminated. Let's analyze the other part(s). A velocity is a distance/time. Do we have that? Yes! -> miles/hour. So, velocity is an option that theoretically fits this question. Buttt... It gives us a time, and acceleration is a change in a velocity (speed, with a direction)/time. So because it says "after 10 minutes", we consider the big picture to be talking about the change in velocity during that time span, which is simplified as "the acceleration" over that time. :)</span>
7 0
3 years ago
Read 2 more answers
A crane can lift a 900 kg mass to height of 50 m in 2 minutes. Calculate the work
Vera_Pavlovna [14]

Answer:

The work done by the crane is, W = 441000 J

The power of the crane is, p = 3675 watts

Explanation:

Given data,

The mass of the object, m = 900 kg

The object is lifted to the height, h = 50 m

The time taken to lift the mass, t = 2 min

                                                      = 120 s

The work done by the crane on the object is equal to the potential energy of the object at that height. It is given by the formula,

                                    W = P.E = mgh joules

Substituting the values in the above equation

                                     W = 900 kg x 9.8 m/s² x 50 m

                                         = 441000 J

The work done by the crane is, W = 441000 J

The power of the crane,

                                  P = W / t

                                     = 441000 J / 120 s

                                     = 3675 watts

Hence, the power of the crane is, p = 3675 watts

8 0
3 years ago
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