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Furkat [3]
4 years ago
7

"Calculate the speed of this sound wave by recording how much time it takes to travel 5 meters. Use the (old school) velocity eq

uation: v = d/t Show units in your work. Answer: 292.39 m/s= 5 meters/.0171 secs." and here's the question I need help with: "Based on the speed you measured above, how long would it take for you to hear thunder if you observed lightning and it was seen to be 1620 meters away?"
Physics
1 answer:
lianna [129]4 years ago
7 0
1) sound velocity reported by you : 292.39 m /s

2) time to travel 1620m at that velocity: t = d / v = 1620 m / 292.39 m/s = 5.54 s, since the moment the sound wave started.

3) You might wanted to tell the time since you watched the lightning.

Then you can calculate the time since the lighting was generated,1620 m away from you, until you saw it, using the speed of light:

 speed of light = 3*10^8 m/s => t = 1620 m / (3*10^8m/s) =0.0000054 s

Then, this time is completely neglectible, and yet the answer is 5.54 s, as calculated in the step 2.
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Diego is trying to lift a piano to the second floor of his house. Diego uses a pulley system and gives a big lift to the piano.T
andreyandreev [35.5K]

Answer:he to

Explanation:

3 0
3 years ago
A 56-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through
aniked [119]

Answer:

a_2=24.5\ \text{m/s}^2 towards right

a_1=2.1875\ \text{m/s}^2 towards left

Explanation:

m_1 = Mass of skater = 56 kg

m_2 = Mass of ball = 5 kg

v = Final velocity of ball = 7 m/s

u = Initial velocity of ball = 0

s = Distance the ball moved in the hand of the skater = 1 m

Moving left is considered and moving right is considered positive.

From kinematic equations of motion we have

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{7^2-0^2}{2\times 1}\\\Rightarrow a=24.5\ \text{m/s}^2

So, the ball will move towards right with a magnitude of acceleration a_2=24.5\ \text{m/s}^2.

The force on the ball will be

F_2=m_2a_2\\\Rightarrow F_2=5\times 24.5\\\Rightarrow F_2=122.5\ \text{N}

The force on the ball is 122.5\ \text{N}

The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

-F_1=F_2\\\Rightarrow -m_1a_1=F_2\\\Rightarrow a_1=-\dfrac{122.5}{56}\\\Rightarrow a_1=-2.1875\ \text{m/s}^2

So, the skater will move towards left with a magnitude of acceleration 2.1875\ \text{m/s}^2

4 0
3 years ago
A plastic light pipe has an index of refraction of 1.48. For total internal reflection, what is the minimum angle of incidence i
Rama09 [41]

Answer:

a) 42.52°

b) 63.98°

Explanation:

Refractive index of pipe = 1.48 = n₂

Refractive index of air = 1.0003 = n₁

\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.0003}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.676\\\Rightarrow \theta_r=42.52^{\circ}

∴ Minimum angle of incidence is 42.52°

Refractive index of water = 1.33 = n₁

\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.33}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.899\\\Rightarrow \theta_r=63.98^{\circ}

∴ Minimum angle of incidence is 63.98°

5 0
4 years ago
If you push a chair across the floor at a cibstant velocity how does the force of friction compare with the force you exert?
Roman55 [17]

-- "constant velocity"   ===>    acceleration is 0 .

-- acceleration=0   ===>   forces are balanced

-- balanced forces   ===>  (friction) + (force you exert)  =  0

                                           (friction) = -(force you exert)

                        They have equal magnitude and opposite direction. 

7 0
4 years ago
Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo
bagirrra123 [75]
By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>
5 0
3 years ago
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