Answer: v = 3.684 m/s
Explanation: The angular frequency (ω) of a loaded spring is given as
ω = √k/m
Where ω = angular frequency, k =spring constant = 11.9 N/m, m = mass of object = 40.1 g = 0.0401 kg.
The velocity of a simple harmonic motion is defied as
v = ω√A² - x²
Where A = Amplitude = 24.7cm = 0.247m and x = displacement.
For our question, we where asked to find velocity at half way, at half way, x = A/2
Hence at half way, x = 0.247/2 = 0.1235 m.
We need to get the value of angular frequency first.
ω = √(11.9/0.0401)
ω = √296.758
ω = 17.22 rad/s.
Then the velocity is
v = 17.22 √0.247² - 0.1235²
v = 17.22 √0.061009 - 0.01525225
v = 17.22 √0.04575675
v = 17.22 × 0.2139
v = 3.684 m/s
The equation you would use here is F=ma, where F is the force in Newtons, m is the mass in kilograms (must be in kilograms in order for the units to match on both sides), and a is acceleration in meters per second squared. Therefore, you do: 65kg x .3m/s^2= FF. That'll give you the answer.
Answer:
The value is
Explanation:
From the question we are told that
The frequency of the second player is
The beat frequency is
The speed of sound is
Generally the frequency of the note played by the first player is mathematically represented as
=>
=>
From the relation of Doppler Shift we have that
Here
So
=>