Answer:
towards right
towards left
Explanation:
= Mass of skater = 56 kg
= Mass of ball = 5 kg
v = Final velocity of ball = 7 m/s
u = Initial velocity of ball = 0
s = Distance the ball moved in the hand of the skater = 1 m
Moving left is considered and moving right is considered positive.
From kinematic equations of motion we have

So, the ball will move towards right with a magnitude of acceleration
.
The force on the ball will be

The force on the ball is 
The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

So, the skater will move towards left with a magnitude of acceleration 
Answer:
a) 42.52°
b) 63.98°
Explanation:
Refractive index of pipe = 1.48 = n₂
Refractive index of air = 1.0003 = n₁

∴ Minimum angle of incidence is 42.52°
Refractive index of water = 1.33 = n₁

∴ Minimum angle of incidence is 63.98°
-- "constant velocity" ===> acceleration is 0 .
-- acceleration=0 ===> forces are balanced
-- balanced forces ===> (friction) + (force you exert) = 0
(friction) = -(force you exert)
They have equal magnitude and opposite direction.
By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span>
=>v¹ = 2.25 m/s (East) </span>