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MaRussiya [10]
3 years ago
5

The temperature of a chemical compound, in degrees Celsius, changes when the compound is exposed to UV light. The table below sh

ows the temperature of the compound, in degrees Celsius, x minutes after the compound is exposed to UV light.
x
0
2
4
6
8
f(x)
15
15.5
17
19.5
23

Write the quadratic function that corresponds to the given table of values in standard form, f(x) = ax2 + bx + c, where a, b and c are constants.
Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

f(x)=0.125x^2+0x+15

Step-by-step explanation:

SIZIF [17.4K]3 years ago
5 0

So, we are given the y intercept, and since we know c is the same as the y value of the y intercept, we know that c=15.

From there we can pick any two of the points given to us to find our a and b.

Let's use (4,17) and (8,23) becase they are whole numbers.

17=16a+4b+15\\ 23=64a+8b+15 \implies \\ 2=16a+4b\\ 8=64a+8b \implies\\ 8=64+16b \\ 8=64+8b \implies \\ 0=8b \implies\\ b=0

So, with b=0, we can plug it back into the first equation to get:17=16a+4b+15 \implies\\ 2=16a \implies\\ a=\frac{1}{8}

So our quadratic is \frac{1}{8}x^2+15

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Compare 4.5x10^6 and 2.1x10^8 explain how you can compare them
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8 0
4 years ago
Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)
iris [78.8K]

The point-slope form:

y-y_1=m(x-x_1)

We have the point (1, 6) and the slope m = 7/3. Substitute:

y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

-7x+3y=11         <em>change the signs</em>

7x-3y=-11

Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

5 0
3 years ago
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