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MaRussiya [10]
3 years ago
5

The temperature of a chemical compound, in degrees Celsius, changes when the compound is exposed to UV light. The table below sh

ows the temperature of the compound, in degrees Celsius, x minutes after the compound is exposed to UV light.
x
0
2
4
6
8
f(x)
15
15.5
17
19.5
23

Write the quadratic function that corresponds to the given table of values in standard form, f(x) = ax2 + bx + c, where a, b and c are constants.
Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

f(x)=0.125x^2+0x+15

Step-by-step explanation:

SIZIF [17.4K]3 years ago
5 0

So, we are given the y intercept, and since we know c is the same as the y value of the y intercept, we know that c=15.

From there we can pick any two of the points given to us to find our a and b.

Let's use (4,17) and (8,23) becase they are whole numbers.

17=16a+4b+15\\ 23=64a+8b+15 \implies \\ 2=16a+4b\\ 8=64a+8b \implies\\ 8=64+16b \\ 8=64+8b \implies \\ 0=8b \implies\\ b=0

So, with b=0, we can plug it back into the first equation to get:17=16a+4b+15 \implies\\ 2=16a \implies\\ a=\frac{1}{8}

So our quadratic is \frac{1}{8}x^2+15

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Hi my lil bunny!

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Let's solve your equation step-by-step.

(\frac{2}{3}x) ( \frac{-6}{7} + \frac{4}{5}) = [\frac{\frac{2^x4}{3} }{5} ] ( \frac{-6}{7} )

\frac{-4}{105} x = \frac{-4x^5}{35}

Step 1: Subtract (-4)/35x^5 from both sides.

\frac{-4}{105} x - \frac{-4}{35x^5} = \frac{-4x^5}{35} - \frac{-4x^5}{35}\\\\\frac{4}{35}x^5  + \frac{-4}{105} = 0

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x(0.114286 x^4 - 0.038095 ) = 0

Step 3: Set factors equal to 0.

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So the answer is :  x = 0 or x = - 0.759836 or x = 0.759836

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In this example we are given two points, (15, 8) and (10, 7), on a straight line.

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