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3 years ago

What type of volcano only ever has quiet eruptions?

1 answer:

3 0

In contrast to quiet eruptions, other volcanoes erupt explosively. Mount St. Helens, for instance, spewed lava high in the air when it erupted. Two things control the type of eruption: how much water vapor and other gasses are in the magma and whether the magma is basaltic or granitic. Basaltic magma tends to ooze out gently in a thin, quiet eruption, while granitic magma is thicker and becomes trapped inside the volcano's vents. Once the pressure grows enough to force out the magma, it explodes.

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John has tied his friend, Zory, a stuffed unicorn to a toy car with a massless string whichmakes an angle of 30°. If he rides fo

Westkost [7]

Answer: A

Since the car is moving to the right, the Normal Force is balancing the Weight and the Net Force is 10 N, right.

Explanation:

as the answers says, the only two forces in the y axis are the normal force and the weight, and they balance each other. On the x axis, you have 20N to the right and the friction is a force that opposes the movement, so the 10N are to the left. The net force is 20 - 10 = 10N.

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3 years ago

An object is placed near a concave mirror having a radius of curvature of magnitude 60 cm. How far should you place the object f

Viefleur [7K]

Answer:

u = 18 cm

Explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm

$m = -\dfrac{v}{u}$

$2.5 = -\dfrac{v}{u}$

v = -2.5 u

now,

Using mirror formula

$\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{1}{-2.5u} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{0.6}{u}$

u = 0.6 x 30

u = 18 cm

distance of object be equal to u = 18 cm

6 0

4 years ago

A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating about a vertical axis with an angular

sp2606 [1]

Answer:

$1.98$ rev/s

Explanation:

$m$ = mass attached to each hand = 5 kg

$r_{i}$ = initial distance of masses in each hand = 1 m

$r_{f}$ = final distance of masses in each hand = 0.1 m

$I$ = moment of inertia of body = 5 kgm²

$I_{i}$ = initial total moment of inertia = $I + 2 mr_{i}^{2}$

$w_{i}$ = initial angular velocity = 1 rev/s

$I_{f}$ = final total moment of inertia = $I + 2 mr_{f}^{2}$

$w_{f}$ = final angular velocity = ?

Using conservation of angular momentum

$I_{i} w_{i} = I_{f} w_{f}$

$(I + 2 mr_{i}^{2}) w_{i} = (I + 2 mr_{f}^{2}) w_{f}$

$(5 + 2 (5) (1)^{2}) (1) = (5 + 2 (5) (0.1)^{2}) w_{f}$

$w_{f} = 2.94$ rev/s

3 0

4 years ago

Read 2 more answers

What acceleration is produced when a 12-N force is exerted on a 3-kg object?

lawyer [7]

Using F=Ma
where a= F/M = 12/3 = 4ms-²

3 0

4 years ago

PLEASE HELP

Anvisha [2.4K]

The speed of the rock at 20 m is 34.3 m/s

Explanation:

We can solve this problem by using the law of conservation of energy: the mechanical energy of the rock, sum of its potential energy + its kinetic energy) must be conserved in absence of air resistance. So we can write:

$U_i +K_i = U_f + K_f$