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3 years ago

What is the formula of the ionic compound formed by the elements lithium and oxygen?

Chemistry

2 answers:

Alex_Xolod [135]3 years ago

8 0

Answer: The chemical formula for the compound of lithium and oxygen will be $Li_2O$

Explanation:

Ionic bond is defined as the bond which is formed when complete transfer of electrons takes place from one atom to another atom.

Lithium is the 3rd element of the periodic table with electronic configuration of $1s^22s^1$

This element looses 1 electron and shows an oxidation state of +1.

Oxygen is the 8th element of the periodic table with electronic configuration $1s^22s^22p^4$

This element will gain 2 electrons and shows an oxidation state of -2.

By criss-cross method, the oxidation state of oxygen becomes the coefficient of lithium and that of lithium becomes of oxygen.

Hence, the chemical formula for the compound obtained by the combination of lithium and oxygen is $Li_2O$

kozerog [31]3 years ago

6 0

The formula is Letter A) Li2O

i got 5 out of 5 on this test on plato.

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If a 0.10 M solution of a colored substance has a maximum absorbance at 500 nm and an absorbance of 0.26 M at this wavelength, w

Mashcka [7]

Absorbance is related to the concentration of a substance using the Beer-Lambert's Law. According to this law, absorbance is linearly related to concentration. However, this is only true up to a certain concentration depending on the substance. For this case, we assume that the said law is applicable.

A = kC
Using the first conditions, ewe solve for k.
0.26 = k (0.10)
k = 2.6

A = kC
A = 2.6 (0.20) = 0.52

Therefore, the absorbance at a concentration of 0.20 M and wavelength of 500nm is 0.52.

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2 years ago

When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.

EleoNora [17]

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

Answer: The % yield of the product is 87.05 %

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

We are given:

Given mass of $CaCO_3$ = 80 g

Molar mass of $CaCO_3$ = 100 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol$

For the given chemical reaction:

$CaCO_3\rightarrow CaO+CO_2$

By stoichiometry of the reaction:

If 1 mole of $CaCO_3$ produces 1 mole of CaO

So, 0.8 moles of $CaCO_3$ will produce = $\frac{1}{1}\times 0.8=0.8mol$ of CaO

We know, molar mass of $CaO$ = 56 g/mol

Putting values in above equation, we get:

$\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g$

The percent yield of a reaction is calculated by using an equation:

$\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100$ ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

$\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%$

Hence, the % yield of the product is 87.05 %

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Answer:

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Explanation:

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