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disa [49]
3 years ago
14

What is the formula of the ionic compound formed by the elements lithium and oxygen?

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
8 0

<u>Answer:</u> The chemical formula for the compound of lithium and oxygen will be Li_2O

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed when complete transfer of electrons takes place from one atom to another atom.

Lithium is the 3rd element of the periodic table with electronic configuration of 1s^22s^1

This element looses 1 electron and shows an oxidation state of +1.

Oxygen is the 8th element of the periodic table with electronic configuration 1s^22s^22p^4

This element will gain 2 electrons and shows an oxidation state of -2.

By criss-cross method, the oxidation state of oxygen becomes the coefficient of lithium and that of lithium becomes of oxygen.

Hence, the chemical formula for the compound obtained by the combination of lithium and oxygen is Li_2O

kozerog [31]3 years ago
6 0
The formula is Letter A) Li2<span>O 

i got 5 out of 5 on this test on plato.</span>
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Find the density of an 8 gram rock if the water in a graduated cylinder rises from 25.0 mL to
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<em>We know that the formula for density is given as </em>

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When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be
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Explanation:

The given precipitation reaction will be as follows.

        AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

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                    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                     0.269 M = \frac{\text{no. of moles}}{1.14 L}

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                   0.307 mol = \frac{mass}{143.32 g/mol}

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