4.60 g of of H₂O form when all the butane burns.
<h3>What is butane ?</h3>
One of the smallest liquid streams frequently created in a refinery is butane. Ten hydrogen atoms and four carbon atoms make up the butane molecule. Typically, butane is either marketed as a finished product or is blended into LPG or gasoline in tiny quantities.
It is frequently employed as a fuel for portable stoves and cigarette lighters, as a propellant in aerosols, as a heating fuel, as a refrigerant, and in the production of a broad variety of goods. Liquefied petroleum gas and butane both exist (LPG).
Butane has a low level of toxicity. In butane misuse, high exposure concentrations can be anticipated. Central nervous system (CNS) and cardiac consequences are the most frequently seen effects in cases of misuse.
To learn more about butane from the given link:
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Answer:
- 178 ºC
Explanation:
The ideal gas law states that :
PV = nRT,
where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.
For the initial conditions :
P₁ V₁ = n₁ R T₁ (1)
and for the final conditions:
P₂V₂= n₂ R T₂ where n₂ = n₁/2 then P₂ V₂ = n₁/2 T₂ (2)
Assuming V₂ = V₁ and dividing (2) by Eqn (1) :
P₂ V₂ = n₁/2 R T₂ / ( n₁ R T₁) then P₂ / P₁ = 1/2 T₂ / T₁
4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K
T₂ = 95 - 273 = - 178 º C
The daughter isotope : Radon-222 (Rn-222).
<h3>Further explanation</h3>
Given
Radium (Ra-226) undergoes an alpha decay
Required
The daughter nuclide
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same
Radium (Ra-226) : ₈₈²²⁶Ra
Alpha particles : ₂⁴He
So Radon-226 emits alpha α particles ₂He⁴ , so the atomic number decreases by 2, mass number decreases by 4
The reaction :
₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn
Firstly, a balanced equation has to be written for the production of ammonia (NH₃) from hydrogen gas (H₂) and nitrogen gas (N₂):
N₂ + 3H₂ → 2NH₃
Now, the mole ratio of N₂ : NH₃ is 1 : 2 based on the coefficients of the balanced equation.
If the moles of N₂ = 2.5 moles
then the moles of NH₃ produced = 2.5 mol × 2
= 5 mol
Thus, the moles of ammonia produced when 2.5 mol of nitrogen gas is combined with excess hydrogen gas is 5 mol.
