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Nikolay [14]
3 years ago
11

I need help with this chem study guide

Chemistry
1 answer:
Cloud [144]3 years ago
7 0
Can you please provide a clearer image?
Thanks
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An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
4 years ago
What type of substance would be best for use in a cooling system?
Sonbull [250]

Answer:

B

Explanation:

<h3><em>Liquid with a low specific heat </em></h3>

3 0
3 years ago
A 5.00 g piece of metal is heated to 100.0 C then placed in a beaker containing 20.0 g of water at 10.0 C. The temperature of th
Nataly [62]
Calculate the heat gained by the water first.

q = mCpΔT
m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C

q = (20.0)(4.186)(5.0) = 419 J

This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)

q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

Cp = -419 / (5.00 • -85.0) = 0.986 J/g°C
5 0
3 years ago
Kathy has been exercising vigorously for the past half hour. her body feels sore and she feels pain in her limbs. what could be
valkas [14]
I believe it is A accumulation of lactic acid in the muscles of her limbs.
5 0
3 years ago
Read 2 more answers
A piece of metal weighing 267.0 g is placed in a graduated cylinder containing 229.0 mL of water. The volume of water now reads
densk [106]

Answer:

9.368g/mL

Explanation:

The density is defined as the mass of a compound in a determined volume.

Based on Archimedes' law, the volume of the piece of metal is the difference between the volume of the water + the inmersed piece - the original volume of water. That is:

<em>Volume of the metal:</em>

257.5mL - 229.0mL = 28.5mL

As the mass of the metal is 267.0g; its density is:

<em>Density:</em>

267.0g / 28.5mL =

<h3>9.368g/mL</h3>
5 0
3 years ago
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