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Nikolay [14]
2 years ago
11

I need help with this chem study guide

Chemistry
1 answer:
Cloud [144]2 years ago
7 0
Can you please provide a clearer image?
Thanks
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Flask contains 0.420 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask. express your an
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Since it talks about the number of particles, we would need the Avogadro's number which is an empirical value equal to 6.022×10²³ particles/mole. Therefore, to determine the number of particles, such as molecules, just multiple the number of moles to the Avogadro's number:

Number of Br₂ molecules = 0.42 mol *6.022×10²³ molecules/mole = 2.53×10²³ molecules
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2 years ago
Ferris & Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.
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Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: <u>For MnO₄⁻ solution</u>-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

<u>For Fe²⁺ solution</u>:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

<u><em>To find out the concentration of Fe²⁺ solution (M₂), we use the equation:</em></u>

\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}

\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}

0.505 = M_{2}\times 3

M_{2} = \frac{0.505}{3} = 0.168M

<u>Therefore, the concentration or molarity of Fe²⁺ solution: </u><u>M₂ = 0.168 M</u>

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3 years ago
An unknown element is shiny and is found to be a good conductor of electricity, what other properties would you predict for it
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That it is hard, and a metal? 
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2 years ago
How many moles of Al are needed to react completely with 1.2 moles of Fe0
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0.8 moles

 3 moles of feO  gives you  2 moles of Al and 1.2 of your moles should give you 1.2 divided by 3*2 so it equals 0.80 moles 

Right?
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3 years ago
Ben works as a medical assistant. He needs to take a patient's vitals, but the patient is refusing to cooperate. He hasn't exper
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Answer:

THE CORRECT ANSWER IS COMMAND.HOPE IT HELP YOU

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2 years ago
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